Database Compatibility Level 101
Each SQL Server database has a setting called Compatibility Level that determines how T-SQL commands are interpreted and what features...
2015-04-12
1,705 reads
Each SQL Server database has a setting called Compatibility Level that determines how T-SQL commands are interpreted and what features...
2015-04-12
1,705 reads
Hi folks! Look, my very first post, yay!
I’ve been thinking about starting my own SQL-related blog for a long time and I guess...
2015-04-04
534 reads
By Steve Jones
This value is something that I still hear today: our best work is done...
By gbargsley
Have you ever received the dreaded error from SQL Server that the TempDB log...
By Chris Yates
Artificial intelligence is no longer a distant concept. It is here, embedded in the...
Hi everyone I am writing an SP where there is logic inside the SP...
Comments posted to this topic are about the item Planning for tomorrow, today -...
We have a BI-application that connects to input tables on a SQL Server 2022...
I try to run this code on SQL Server 2022. All the objects exist in the database.
CREATE OR ALTER VIEW OrderShipping AS SELECT cl.CityNameID, cl.CityName, o.OrderID, o.Customer, o.OrderDate, o.CustomerID, o.cityId FROM dbo.CityList AS cl INNER JOIN dbo.[Order] AS o ON o.cityId = cl.CityNameID GO CREATE OR ALTER FUNCTION GetShipCityForOrder ( @OrderID INT ) RETURNS VARCHAR(50) WITH SCHEMABINDING AS BEGIN DECLARE @city VARCHAR(50); SELECT @city = os.CityName FROM dbo.OrderShipping AS os WHERE os.OrderID = @OrderID; RETURN @city; END; goWhat is the result? See possible answers