2017-12-13
324 reads
2017-12-13
324 reads
This post is a public service announcement for all users of macOS High Sierra (10.13). (Note: Apple has already released...
2017-12-06
547 reads
Note: This is content that I originally wrote for our upcoming book, SQL Server 2017 Administration Inside Out, that did...
2017-11-29
707 reads
In the grand scheme of things, MySQL and SQL Server operate in different realms. It’s difficult to compare them because...
2017-11-22
346 reads
For the last five months or so, I have been helping some really smart people put words on paper, both...
2017-11-15
576 reads
Ewald Cress writes: Find a person or several people to pick on, and tell us a shareable story or two...
2017-11-14
327 reads
I love theatre. In six months I am putting on two one-act plays for a local festival, because I don’t...
2017-11-08
340 reads
I have a favourite new feature of SQL Server Management Studio 17.3 (SSMS), and that’s XE Profiler, which allows you to...
2017-11-01
496 reads
This is more for my benefit in the future, but hopefully it can help someone else too. We recently had...
2017-10-25
4,479 reads
Recently, I was asked to assist an organization with getting their data back for a SQL Server that had experienced...
2017-10-18
649 reads
By ReviewMyDB
My T-SQL Tuesday #202 entry for Marlon Ribunal's invitation on memorable SQL Server outages....
A RAG pipeline that answers questions in the demo is not the same thing...
By Steve Jones
“A multitude of bad ideas is necessary for one good idea” – from Excellent...
Comments posted to this topic are about the item Adding new column with DEFAULT
I've got a web application for my side business. I've added a SQL Server...
Comments posted to this topic are about the item Looking for New Blood
Which number will the COUNT() return after executing the following statements:
DROP TABLE IF EXISTS #test; CREATE TABLE #test (id INT) INSERT INTO #test (id) SELECT * FROM GENERATE_SERIES(1, 3) AS gs ; ALTER TABLE #test ADD flag BIT CONSTRAINT DF_#test_flag DEFAULT 0; go UPDATE #test SET flag = 0 WHERE id = 1 UPDATE #test SET flag = 1 WHERE id = 2 INSERT INTO #test (id) VALUES (4) SELECT COUNT(*) FROM #test AS t WHERE flag = 0See possible answers