A Month of PowerShell – Day 15 (Databases: Adding Foreign Keys)
Welcome to Day 15 of my “A Month of PowerShell” series. This series will use the series landing page on...
2013-02-15
725 reads
Welcome to Day 15 of my “A Month of PowerShell” series. This series will use the series landing page on...
2013-02-15
725 reads
Welcome to Day 14 of my “A Month of PowerShell” series. This series will use the series landing page on...
2013-02-14
2,138 reads
Welcome to Day 13 of my “A Month of PowerShell” series. This series will use the series landing page on...
2013-02-20 (first published: 2013-02-13)
2,953 reads
Welcome to Day 12 of my “A Month of PowerShell” series. This series will use the series landing page on...
2013-02-12
1,336 reads
Welcome to Day 11 of my “A Month of PowerShell” series. This series will use the series landing page on...
2013-02-11
4,751 reads
Welcome to Day 10 of my “A Month of PowerShell” series. This series will use the series landing page on...
2013-02-13 (first published: 2013-02-10)
2,718 reads
Welcome to Day 9 of my “A Month of PowerShell” series. This series will use the series landing page on...
2013-02-09
6,048 reads
Welcome to Day 8 of my “A Month of PowerShell” series. This series will use the series landing page on...
2013-02-08
688 reads
Welcome to Day 7 of my “A Month of PowerShell” series. This series will use the series landing page on...
2013-02-07
1,853 reads
Welcome to Day 6 of my “A Month of PowerShell” series. This series will use the series landing page on...
2013-02-06
779 reads
By Chris Yates
The New Arena of Leadership The role of the Chief Data Officer is no...
Presenting you with an updated version of our sp_snapshot procedure, allowing you to easily...
SELECT * feels convenient, but in SQL Server it bloats I/O, burns network bandwidth,...
Comments posted to this topic are about the item Cleaning Up the Cloud
Comments posted to this topic are about the item The Maximum Value in the...
Comments posted to this topic are about the item Oracle Performance Tuning: Practical Techniques...
I have a table with this data:
TravelLogID CityID StartDate EndDate 1 1 2025-01-01 2025-01-06 2 2 2025-01-01 2025-01-06 3 3 2025-01-01 2025-01-06 4 4 2025-01-01 2025-01-06 5 5 2025-01-01 2025-01-06I run this code:
SELECT IDENT_CURRENT('TravelLog')I get the value 5 back. Now I do this:
SET IDENTITY_INSERT dbo.TravelLog ON INSERT dbo.TravelLog ( TravelLogID, CityID, StartDate, EndDate ) VALUES (25, 5, '2025-09-12', '2025-09-17') SET IDENTITY_INSERT dbo.TravelLog OFFI now run this code.
DBCC CHECKIDENT(TravelLog) GO INSERT dbo.TravelLog ( CityID, StartDate, EndDate ) VALUES (4, '2025-10-14', '2025-10-17') GOWhat is the value for TravelLogID for the row I inserted for CityID 4 and dates starting on 14 Oct 2025? See possible answers