The Video World
I wonder what you think of this: video shorts. I've gottne the Lockergnome newsletters for years and they've proven interesting...
2007-07-06
601 reads
I wonder what you think of this: video shorts. I've gottne the Lockergnome newsletters for years and they've proven interesting...
2007-07-06
601 reads
I just got my author copies of the Sybex book for exam 70-444 and have to say the book looks...
2007-07-05
729 reads
One of the suggestions I saw today was to add blogs to the user profile on the site and not...
2007-07-05
639 reads
I wrote an article recently on the Journey To Katmai, looking at some of the new features that are coming...
2007-07-04
658 reads
Breaking Up is Easy to DoHardIt's nice to be able to package a process into a single, tidy, elegant query,...
2007-07-03
597 reads
Some of you younger DBA’s out there may not know who Neil Sedaka is or remember his poignant words "Breaking...
2007-07-03
606 reads
Most people I know tend to work in one of two places consistently: work or home. So they've built a...
2007-07-03
569 reads
This is pretty cool, a, earthquake test for Project Black Box from Sun. They take one of their systems to...
2007-07-01
630 reads
The active SQL Server error log is one of the first places people look when there is a problem. For...
2007-06-29
1,592 reads
No, I'm not going to keep making corny references to war and being a soldier. But in many ways, we...
2007-06-29
1,335 reads
By gbargsley
We’ve all been there. Someone walks up and asks, “Is SQL Server having issues?”...
By Chris Yates
In the beginning, there was OLTP – Online Transaction Processing. Fast, reliable, and ruthlessly...
One thing I’ve always loved about the Scooby-Doo cartoon is that he never solved...
Hello SQL Server 2022 16.0.4212.1 running on a Windows Server 2025 Std,V 24H2, SO...
i have subscription of github copilot which i can access in vs 2022 comunity...
Comments posted to this topic are about the item Password Guidance
What happens if you run the following code in SQL Server 2022+?
declare @t1 table (id int); insert into @t1 (id) values (NULL), (1), (2), (3); select count(*) from @t1 where @t1.id is distinct from NULL;See possible answers