Starting Conversations - Part 2
A week or so ago I posted a note about reading How to Start a Conversation and Make Friends (worth...
2009-04-15
385 reads
A week or so ago I posted a note about reading How to Start a Conversation and Make Friends (worth...
2009-04-15
385 reads
A reminder of one of the downsides of working is today: Tax Day. In the US, income tax filing is...
2009-04-15
867 reads
I happen to notice this in a class recently that I had the rare student - one that could take notes...
2009-04-14
400 reads
I read SQLBatman's post about his first week as an MVP, and it really resonated well with me. I think...
2009-04-14
647 reads
I've been writing a lot about networking lately and my efforts to learn/leverage LinkedIn, and along the way taken a...
2009-04-13
825 reads
I currently write the editorial for the PASS Connector which is published every two weeks as part of my role...
2009-04-13
291 reads
Time has flown by since my last update, busy time at work and struggling to get that done and find...
2009-04-13
392 reads
Yesterday, I drove the Smart down to Burlington/Colchester, Vermont to meet up with MVP Roman Rehak and speak to the local...
2009-04-13
1,081 reads
I'm embarking on another book project. Not writing this time, but tech editing again. I tech edited a book last...
2009-04-13
623 reads
I’ve often described SQL Server to people new to databases as a data pump.
Just like a water pump, you...
2009-04-13
1,231 reads
By Steve Jones
“Don’t aim to have others like you; aim to have them respect you.” –...
If you work with data pipelines, SQL, notebooks, or machine learning models, a Mac...
By ChrisJenkins
Have you been thinking about migrating your reporting to Microsoft Fabric or Snowflake but...
Comments posted to this topic are about the item SQL Art, Part 4: Happy...
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In SQL Server 2025, I have a table (dbo.UserPermission) that contains this data:
UserID UserPermissions 15 23 37What is returned when I run this code:
select bit_count(UserPermissions) as PermissionCount from dbo.UserPermission where UserID = 3;See possible answers