PASS Update #27
I’m just back from the March 2010 Board meeting and it went better than usual (for any meeting). Most of...
2010-03-24
588 reads
I’m just back from the March 2010 Board meeting and it went better than usual (for any meeting). Most of...
2010-03-24
588 reads
The MSDN - Microsoft, has collected too much info about features supported by the SQL Server 2008 R2, for all editions...
2010-03-24
1,231 reads
It’s getting close to that time of year when you can apply to run for the PASS Board of Directors....
2010-03-24
1,645 reads
I've been using the scripting tools in SSIS for some time, but I came across something today that I can't...
2010-03-23
2,171 reads
Yesterday I wrote about expectations at free events, basically saying they don’t differ a lot from paid events. The next...
2010-03-23
560 reads
I was reading through the latest XML Workshop article that I have from Jacob Sebastian. It’s a fantastic series for...
2010-03-23
2,045 reads
And to wrap up the miniseries on IN, EXISTS and JOIN, a look at NOT EXISTS and LEFT OUTER JOIN...
2010-03-23
12,082 reads
I recently posted a couple of scripts that backup all databases on your SQL Server instance to disk with a...
2010-03-23
1,319 reads
Update: The problem posts have been removed from the SQLTechConsulting site.
I ran across a note from Brent Ozar (blog | Twitter)...
2010-03-23
1,790 reads
New York, New York, it’s a hell of a town. The Bronx is up and the Battery’s down. The people...
2010-03-23
551 reads
By Chris Yates
The New Arena of Leadership The role of the Chief Data Officer is no...
Presenting you with an updated version of our sp_snapshot procedure, allowing you to easily...
SELECT * feels convenient, but in SQL Server it bloats I/O, burns network bandwidth,...
I've noticed several instances of what looks like a recursive insert with the format:...
Comments posted to this topic are about the item Cleaning Up the Cloud
Comments posted to this topic are about the item The Maximum Value in the...
I have a table with this data:
TravelLogID CityID StartDate EndDate 1 1 2025-01-01 2025-01-06 2 2 2025-01-01 2025-01-06 3 3 2025-01-01 2025-01-06 4 4 2025-01-01 2025-01-06 5 5 2025-01-01 2025-01-06I run this code:
SELECT IDENT_CURRENT('TravelLog')I get the value 5 back. Now I do this:
SET IDENTITY_INSERT dbo.TravelLog ON INSERT dbo.TravelLog ( TravelLogID, CityID, StartDate, EndDate ) VALUES (25, 5, '2025-09-12', '2025-09-17') SET IDENTITY_INSERT dbo.TravelLog OFFI now run this code.
DBCC CHECKIDENT(TravelLog) GO INSERT dbo.TravelLog ( CityID, StartDate, EndDate ) VALUES (4, '2025-10-14', '2025-10-17') GOWhat is the value for TravelLogID for the row I inserted for CityID 4 and dates starting on 14 Oct 2025? See possible answers