Growing the Pool of SQL Speakers – Part 3
Continuing on from Part 2, I want to continue this time with two points I left open last time:
How to...
2010-03-31
1,660 reads
Continuing on from Part 2, I want to continue this time with two points I left open last time:
How to...
2010-03-31
1,660 reads
When I wrote my most recent free eBook, Brad’s Sure Guide to SQL Server Maintenance Plans, some of the DBAs...
2010-03-31
2,294 reads
Recently, we found out that HP Data Protector had an update, and I took for granted that this update would...
2010-03-31
12,434 reads
I recently came across an interesting script to help show index info and usage. As I began to dissect the...
2010-03-31
1,995 reads
Intel has finally released the long awaited (at least by me) 45nm Xeon 7500 series processor. This beast has eight...
2010-03-31
1,996 reads
The family returned back from the UK last night, after traveling for something like 14 hours, plus an early morning...
2010-03-31
1,546 reads
Have you been looking for a way to measure report performance? Want to know who accesses your reports most frequently? ...
2010-03-30
1,713 reads
I’ve long admired the value that I get from Wikipedia and like the concept of crowd sourcing knowledge, just never...
2010-03-30
1,630 reads
So the other day I posted, Slipstream - Makes installs simple, and this afternoon I needed to do a SQL Server...
2010-03-30
1,399 reads
I had bigger plans for this series than what has transpired. I think that is a testament as to how...
2010-03-30
1,939 reads
By Steve Jones
ecstatic shock – n. a surge of energy upon catching a glimpse from someone...
By Chris Yates
The New Arena of Leadership The role of the Chief Data Officer is no...
Presenting you with an updated version of our sp_snapshot procedure, allowing you to easily...
I've noticed several instances of what looks like a recursive insert with the format:...
Comments posted to this topic are about the item Cleaning Up the Cloud
Comments posted to this topic are about the item The Maximum Value in the...
I have a table with this data:
TravelLogID CityID StartDate EndDate 1 1 2025-01-01 2025-01-06 2 2 2025-01-01 2025-01-06 3 3 2025-01-01 2025-01-06 4 4 2025-01-01 2025-01-06 5 5 2025-01-01 2025-01-06I run this code:
SELECT IDENT_CURRENT('TravelLog')I get the value 5 back. Now I do this:
SET IDENTITY_INSERT dbo.TravelLog ON INSERT dbo.TravelLog ( TravelLogID, CityID, StartDate, EndDate ) VALUES (25, 5, '2025-09-12', '2025-09-17') SET IDENTITY_INSERT dbo.TravelLog OFFI now run this code.
DBCC CHECKIDENT(TravelLog) GO INSERT dbo.TravelLog ( CityID, StartDate, EndDate ) VALUES (4, '2025-10-14', '2025-10-17') GOWhat is the value for TravelLogID for the row I inserted for CityID 4 and dates starting on 14 Oct 2025? See possible answers