Missing European PASS (Updated)
As most of you know, the Icelandic volcano has played havoc with travel plans for speakers coming from the US...
2010-04-19
458 reads
As most of you know, the Icelandic volcano has played havoc with travel plans for speakers coming from the US...
2010-04-19
458 reads
First let me say, I know my Powershell skills are sub-par. I’m working on it. Slowly but surely. That said,...
2010-04-19
1,198 reads
I’ve had this on my list to write about for a while, just didn’t have a great example until this...
2010-04-19
496 reads
I hear that registration is over 350 so far, with seats still available – but register soon! I’m driving up with...
2010-04-19
499 reads
Spring fever is running hot here in Parker, Colorado, after a long winter. Last year, I put in a Square...
2010-04-19
791 reads
Microsoft has released SQL Server 2005 SP3 Cumulative Update 9, which is Build 4294. I count 13 fixes in this...
2010-04-19
1,077 reads
Happy Monday, everyone! The internet is a buzz! I have never seen so much energy and enthusiasm as SQLSaturdays, and...
2010-04-19
1,040 reads
The DMV for Day 18 is sys.dm_clr_tasks, which is described by BOL as:
Returns a row for all common language runtime...
2010-04-18
1,709 reads
Compiled by Abi Chapagai (April 2010)
Implementation of High Availability depends in the need of the business. Each of the technologies...
2010-04-18
24,332 reads
I just finished reading “The next wave of technologies” by Phil Simon. A great read! It proposes a...
2010-04-18
5 reads
By Steve Jones
ecstatic shock – n. a surge of energy upon catching a glimpse from someone...
By Chris Yates
The New Arena of Leadership The role of the Chief Data Officer is no...
Presenting you with an updated version of our sp_snapshot procedure, allowing you to easily...
Comments posted to this topic are about the item Lessons from the Postmark-MCP Backdoor
Just saw the "Azure Extension for SQL Server" Does anyone has experience with it?...
I've noticed several instances of what looks like a recursive insert with the format:...
I have a table with this data:
TravelLogID CityID StartDate EndDate 1 1 2025-01-01 2025-01-06 2 2 2025-01-01 2025-01-06 3 3 2025-01-01 2025-01-06 4 4 2025-01-01 2025-01-06 5 5 2025-01-01 2025-01-06I run this code:
SELECT IDENT_CURRENT('TravelLog')I get the value 5 back. Now I do this:
SET IDENTITY_INSERT dbo.TravelLog ON INSERT dbo.TravelLog ( TravelLogID, CityID, StartDate, EndDate ) VALUES (25, 5, '2025-09-12', '2025-09-17') SET IDENTITY_INSERT dbo.TravelLog OFFI now run this code.
DBCC CHECKIDENT(TravelLog) GO INSERT dbo.TravelLog ( CityID, StartDate, EndDate ) VALUES (4, '2025-10-14', '2025-10-17') GOWhat is the value for TravelLogID for the row I inserted for CityID 4 and dates starting on 14 Oct 2025? See possible answers