A DMV a Day – Day 27
The DMV for Day 27 is sys.dm_tran_locks, which is described by BOL as:
Returns information about currently active lock manager resources....
2010-04-27
7,536 reads
The DMV for Day 27 is sys.dm_tran_locks, which is described by BOL as:
Returns information about currently active lock manager resources....
2010-04-27
7,536 reads
For the April T-SQL Tuesday, I blogged about a report to find information on the BLOBs in a database. I...
2010-04-27
1,223 reads
Over the last several months I’ve had a look at IN, Exists, Join and their opposites to see how they...
2010-04-27
1,337 reads
Available for download by all PASS members (membership is free), this issue has Techies Talking to Non-Techies by Don Gabor....
2010-04-27
623 reads
Tia thinks I’m crazy to book early, but I like to have a choice of flights, and I like to...
2010-04-27
774 reads
Last year at the PASS Summit we held a silly little event called Kilt Wednesday. Only three people took part,...
2010-04-27
1,399 reads
This is the official announcement that we are officially scheduled for holding a SQL Saturday in Columbia, SC, on October...
2010-04-27
879 reads
Since SQL Server 2008 R2 has gone RTM, and will be available on MSDN Subscribers on May 3, I thought...
2010-04-27
1,924 reads
For my next series of blog posts I intend to document and write about SQL Server replication. This is a...
2010-04-27
2,476 reads
I had the opportunity to go present at SQLSaturday #41-Atlanta this past weekend (April 24, 2010) and I had a...
2010-04-27
815 reads
By Steve Jones
ecstatic shock – n. a surge of energy upon catching a glimpse from someone...
By Chris Yates
The New Arena of Leadership The role of the Chief Data Officer is no...
Presenting you with an updated version of our sp_snapshot procedure, allowing you to easily...
Comments posted to this topic are about the item Lessons from the Postmark-MCP Backdoor
Just saw the "Azure Extension for SQL Server" Does anyone has experience with it?...
I've noticed several instances of what looks like a recursive insert with the format:...
I have a table with this data:
TravelLogID CityID StartDate EndDate 1 1 2025-01-01 2025-01-06 2 2 2025-01-01 2025-01-06 3 3 2025-01-01 2025-01-06 4 4 2025-01-01 2025-01-06 5 5 2025-01-01 2025-01-06I run this code:
SELECT IDENT_CURRENT('TravelLog')I get the value 5 back. Now I do this:
SET IDENTITY_INSERT dbo.TravelLog ON INSERT dbo.TravelLog ( TravelLogID, CityID, StartDate, EndDate ) VALUES (25, 5, '2025-09-12', '2025-09-17') SET IDENTITY_INSERT dbo.TravelLog OFFI now run this code.
DBCC CHECKIDENT(TravelLog) GO INSERT dbo.TravelLog ( CityID, StartDate, EndDate ) VALUES (4, '2025-10-14', '2025-10-17') GOWhat is the value for TravelLogID for the row I inserted for CityID 4 and dates starting on 14 Oct 2025? See possible answers