Sheldon Hull

https://github.com/sheldonhull

Blog Post

go

Starter Template
I saved this as a snippet for vscode to get up and running quickly with something better than the defaults for handling func main isolation.
I’ve been working on...

2020-10-30

25 reads

Blog Post

shell

Installing go-task
This tool is great for cross-platform shell scripting as it runs all the commands in the Taskfile.yml using a built in go shell library that supports bash syntax...

2020-10-30

28 reads

Blog Post

Getting Started with Stream Analytics

Resources

Resources

If you want a schema reference for the json Application Insights produces // [Azure Application Insights Data Model // Microsoft Docs

](http://bit.ly/2S3kFlD)

If you want to visualize last 90 days of...

2020-07-25

24 reads

Blogs

Optimising Costs: Strategies for Efficient Cloud Resource Management

By

Over time, I’ve realised that one of the hardest parts of cloud management isn’t...

Cost Visibility: Tracking and Analysing Your Cloud Spend

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One of the biggest challenges I’ve faced in cloud operations is maintaining clear visibility...

Whiling away an afternoon, thinking

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I come to Heathrow often. Today is likely somewhere close to 60 trips to...

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Forums

Fun with JSON II

By Steve Jones - SSC Editor

Comments posted to this topic are about the item Fun with JSON II

Changing Data Types

By Steve Jones - SSC Editor

Comments posted to this topic are about the item Changing Data Types

Answering Questions On Dropped Columns

By Cláudio Silva

Comments posted to this topic are about the item Answering Questions On Dropped Columns

Visit the forum

Question of the Day

Fun with JSON II

I have some data in a table:

CREATE TABLE #test_data
(
    id INT PRIMARY KEY,
    name VARCHAR(100),
    birth_date DATE
);

-- Step 2: Insert rows  
INSERT INTO #test_data
VALUES
(1, 'Olivia', '2025-01-05'),
(2, 'Emma', '2025-03-02'),
(3, 'Liam', '2025-11-15'),
(4, 'Noah', '2025-12-22');
If I run this query, how many rows are returned?
SELECT t1.[key] AS row,
       t2.*
FROM OPENJSON(
     (
         SELECT t.* FROM #test_data AS t FOR JSON PATH
     )
             ) t1
    CROSS APPLY OPENJSON(t1.value) t2;

See possible answers