Technical Article

Date/Time formatting function

T-SQL analog for Visual Basic FORMAT function. Created for MSSQL 2000. Works regardless of language settins on server or client side! fn_format('YYYY/DD/MM HH:MI','2002-03-13 12:00') = '2002/13/03 12:00' fn_format('DD.MM.YY','2002-03-13 12:00:00') = '13.03.02' fn_format('HH:MI:SS','2002-03-13 12:00:00') = '12:00:00'

You rated this post out of 5. Change rating

2002-02-05

985 reads

Technical Article

Splitting string of values to table

This function can convert string with separated values to table. Exclusive feature: items inside quotes will not be splitted! Now you can easily perform joins on CSV strings! For expample: fn_split('1, 2, ''3, 4'', 5',',')= 1 2 3, 4 5 First parameter - string with values, second - delimiter character.

(1)

You rated this post out of 5. Change rating

2002-02-05

1,203 reads

Blogs

Advice I Like: Respect

By

“Don’t aim to have others like you; aim to have them respect you.” –...

Blue Sky Programming – The Optimism Trap

By

Many years ago, before I joined Oracle, I was working on a major modernisation...

Setting Up a Mac for Data Engineering and AI Work

By

If you work with data pipelines, SQL, notebooks, or machine learning models, a Mac...

Read the latest Blogs

Forums

SQL Art, Part 4: Happy 4th of July — A British DBA's Guide to Celebrating a War We Don't Talk About

By Terry Jago

Comments posted to this topic are about the item SQL Art, Part 4: Happy...

locking down agent for new user on our dev machine

By stan

hi , a new user wants to be able to add sql agent jobs...

SQL Server Enum Implementation: A Single-Row View Strategy for Avoiding Magic Values

By Ivica Borscak

Comments posted to this topic are about the item SQL Server Enum Implementation: A...

Visit the forum

Question of the Day

BIT_COUNT I

In SQL Server 2025, I have a table (dbo.UserPermission) that contains this data:

UserID  UserPermissions
15
23
37
What is returned when I run this code:
select bit_count(UserPermissions) as PermissionCount
from dbo.UserPermission
where UserID = 3;

See possible answers