Getting ready for the third “Industrial Revolution”: Database 2010-2015
I searched the internet for “connect and forget”. Wonderbox.net offer is described as a...
2010-10-10
81 reads
I searched the internet for “connect and forget”. Wonderbox.net offer is described as a...
2010-10-10
81 reads
10 years ago IT professionals considered database technology “mature” and analysts were preparing to...
2010-09-13
57 reads
“The information age is an idea that the current era will be characterized by the ability of...
2010-08-22
51 reads
“Content is king” is the golden rule of the SEO. The semantic web is all about data. Any web...
2010-06-25
58 reads
Microsoft is associated almost exclusively with Windows and Office. Unfortunately a lot more...
2010-05-15
56 reads
I just finished reading “The next wave of technologies” by Phil Simon. A great read! It proposes a...
2010-04-18
46 reads
The 2008 trending topic everyone was talking about was the Web 2.0. On October 23 that same year,...
2010-04-02
72 reads
2001-01-01
86 reads
By Steve Jones
I caught this interesting item over on Pinal Dave’s blog: Eleven Interview Questions that...
By Hemantgiri
I use color-coded connections in SSMS to distinguish Production, Pre-Production, UAT, and Development. But...
WhatsApp CS 628218520154 Jl. Suryopranoto No.40, RT.12/RW.7, Petojo Utara, Kecamatan Gambir, Kota Jakarta Pusat,...
WhatsApp CS 628218520154 Jl. Pegangsaan Timur No.1, Cikini, Kec. Menteng, Kota Jakarta Pusat, Daerah...
WhatsApp CS 628218520154 Jl. Pintu Air Raya No.36 Q, RT.6/RW.1, Ps. Baru, Kecamatan Sawah...
I have some data in a SQL Server 2025 database. It looks like this for the dbo.Customer table:
CustomerID CustomerName PreferredName 1 Steve Steve 2 Andy Andy 3 Brian Brian 4 Allan Allan 5 Devin Devin 6 Steve Steve 7 Sally SallyI want to detect which names have a single trailing space. The CustomerName is a varchar() and the PreferredName is a CHAR(). Does this query detect the problem rows?
SELECT
CustomerID,
CustomerName,
PreferredName
FROM Customer
WHERE CustomerName <> RTRIM(CustomerName)
OR PreferredName <> RTRIM(PreferredName); See possible answers