Meagan Longoria

Meagan Longoria is a consultant with Denny Cherry & Associates in Denver, CO where she shares her expertise in Microsoft BI and data warehousing through solution envisioning, architecture design, solution development, training, and blogging. She is a speaker at user groups and conferences across the country.

Blogs

Why Optimize CPU for RDS SQL Server is a game changer

By

One feature that I have been waiting for years! The new announcement around optimize...

Performance tuning KubeVirt for SQL Server

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Following on from my last post about Getting Started With KubeVirt & SQL Server,...

T-SQL Tuesday #193 – A Note to Your Past, and a Warning from Your Future

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I haven’t posted in a while (well, not here at least since I’ve been...

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Forums

FARE Labs Pvt. Ltd. is the best water testing facility in India.

By farelabs

Accurate water test results are provided by the Fare facility, an Indian water testing...

i noticed the sqlhealth extende event is on by default , so can i reduce

By rajemessage 14195

hi, i noticed the sqlhealth extended event is on by default , and it...

Looking for advice on improving SQL Server performance for a service management

By workman

Hi everyone, I’m looking for some guidance on a SQL Server performance issue I’ve...

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Question of the Day

The Read Committed Snapshot Isolation behaviour

I am currently working with Sql Server 2022 and AdventureWorks database. First of all, let's set the "Read Committed Snapshot" to ON:

use master;
go

alter database AdventureWorks set read_committed_snapshot on with no_wait;
go
Then, from Session 1, I execute the following code:
--Session 1
use AdventureWorks;
go

create table ##t1 (id int, f1 varchar(10));
go

insert into ##t1 values (1, 'A');
From another session, called Session 2, I open a transaction and execute the following update:
--Session 2
use AdventureWorks;
go

begin tran;
update ##t1 
set f1 = 'B'
where id = 1;
Now, going back to Session 1, what happens if I execute this statement?
--Session 1
select f1
from ##t1
where id = 1;
 

See possible answers