Linked Servers are an interesting technology in SQL Server to allow remote access from within the database to external data sources. They can be a boon in a heterogenous environment with other Oracle, DB2, etc. data sources. But they can also help in a smaller scale against those "hidden" datasources like Excel or Access. New Author Krishna.
2007-10-02 (first published: 2004-06-02)
48,025 reads
2004-10-29
2,680 reads
If we give SP_HELP , we'll know to which File Group the table belongs.If we give SP_HELPFILEGROUP , we'll know the logical and physical file names along with other information that belong to the given File Group. But have you ever tried that, given a file group, how to find all the tables that belong […]
2004-05-10
142 reads
It is a very simple but useful SP to get Trigger and related table info especially on databases having large number of tables.
2002-09-19
335 reads
By Steve Jones
Superheroes and saints never make art. Only imperfect beings can make art because art...
One feature that I have been waiting for years! The new announcement around optimize...
Following on from my last post about Getting Started With KubeVirt & SQL Server,...
Comments posted to this topic are about the item The AI Bubble and the...
Hi, in a simple oledb source->derived column->oledb destination data flow, 2 of my...
hi, i noticed the sqlhealth extended event is on by default , and it...
I am currently working with Sql Server 2022 and AdventureWorks database. First of all, let's set the "Read Committed Snapshot" to ON:
use master; go alter database AdventureWorks set read_committed_snapshot on with no_wait; goThen, from Session 1, I execute the following code:
--Session 1 use AdventureWorks; go create table ##t1 (id int, f1 varchar(10)); go insert into ##t1 values (1, 'A');From another session, called Session 2, I open a transaction and execute the following update:
--Session 2 use AdventureWorks; go begin tran; update ##t1 set f1 = 'B' where id = 1;Now, going back to Session 1, what happens if I execute this statement?
--Session 1 select f1 from ##t1 where id = 1;See possible answers