2005-12-28
1,217 reads
2005-12-28
1,217 reads
2005-12-20
1,238 reads
Saw this at the book store this evening and picked it up.
SQL Server 2005 Administrator's Pocket Consultant
I'll spend the...
2005-12-18
1,489 reads
This is one of those "bang head here" issues. I was trying to install
Net::SSH::Perl, which basically drives SSH through Perl,...
2005-12-16
1,789 reads
In a community the size of SQL Server Central, it's natural for people
to come and go, especially with contributions to...
2005-12-15
1,318 reads
2005-12-14
1,356 reads
Had a need for this the other day. We just needed a quick dump of which
drives each database was using....
2005-12-09
1,365 reads
I saw this first on Karen Watterson's blog. Microsoft has released an update to SQL Server 2005's Books Online:
Download
A quick...
2005-12-07
1,455 reads
2005-12-07
1,269 reads
Slowly reworking my professional site at http://www.truthsolutions.com/
but as of right now it's more of a brochure site than anything else....
2005-11-30
1,283 reads
By Chris Yates
The New Arena of Leadership The role of the Chief Data Officer is no...
Presenting you with an updated version of our sp_snapshot procedure, allowing you to easily...
SELECT * feels convenient, but in SQL Server it bloats I/O, burns network bandwidth,...
Comments posted to this topic are about the item Cleaning Up the Cloud
Comments posted to this topic are about the item The Maximum Value in the...
Comments posted to this topic are about the item Oracle Performance Tuning: Practical Techniques...
I have a table with this data:
TravelLogID CityID StartDate EndDate 1 1 2025-01-01 2025-01-06 2 2 2025-01-01 2025-01-06 3 3 2025-01-01 2025-01-06 4 4 2025-01-01 2025-01-06 5 5 2025-01-01 2025-01-06I run this code:
SELECT IDENT_CURRENT('TravelLog')I get the value 5 back. Now I do this:
SET IDENTITY_INSERT dbo.TravelLog ON INSERT dbo.TravelLog ( TravelLogID, CityID, StartDate, EndDate ) VALUES (25, 5, '2025-09-12', '2025-09-17') SET IDENTITY_INSERT dbo.TravelLog OFFI now run this code.
DBCC CHECKIDENT(TravelLog) GO INSERT dbo.TravelLog ( CityID, StartDate, EndDate ) VALUES (4, '2025-10-14', '2025-10-17') GOWhat is the value for TravelLogID for the row I inserted for CityID 4 and dates starting on 14 Oct 2025? See possible answers