Joyful Crafsmen is a young company designing, constructing and operating business intelligence solutions for enterprises. People behind are experts in Microsoft Data Platform, which includes SQL Server, Microsoft Azure, Power BI and other leading edge Microsoft technologies. Sharing our know-how with others is our other love. Through training, consulting, and teaching in our community, we help others to be better and better every day.

Blog Post

Microsoft Fabric

What will be much easier with Microsoft Fabric?
Microsoft Fabric is built on a foundation of Software as a Service (SaaS), which takes simplicity and integration to a whole new...

2023-07-24 (first published: )

387 reads

Blogs

T-SQL Tuesday #181: A Technology Present

By

It’s the last T-SQL Tuesday of the year, and it’s amazing to think we’ve...

Trace Flag 3625 Follow Up

By

Several months ago, I discussed my customer’s intention to enable trace flag 3625. Since...

Top 5 Advanced SQL Courses for 2025 (Must-Know)

By

Want to seriously boost your data skills? Mastering advanced SQL is the key, whether...

Read the latest Blogs

Forums

Group records during capture

By Bruin

I have a table which is being written to by another application. A few...

Peer review SQL Central articles

By Srinivasarao Daruna

Hi, I would like to contribute to SQLServerCentral in peer reviews. As there are...

Getting ANY of the data

By Steve Jones - SSC Editor

Comments posted to this topic are about the item Getting ANY of the data

Visit the forum

Question of the Day

Getting ANY of the data

I have this data in two tables:

-- Beer table
BeerIDBeerNamebrewer
5Becks    Interbrew
6Fat Tire   New Belgium
7Mac n Jacks  Mac & Jack's Brewery
8Alaskan AmberAlaskan Brewing 
9Kirin        Kirin Brewing

-- Beercount table
BeerName      BottleCount
Becks         5
Fat Tire      1
Mac n Jacks   2
Alaskan Amber 4
NULL          7
Corona        2
Tsing Tao     4
Kirin         12
What is returned from this query?
SELECT *
FROM dbo.BeerCount AS bc
WHERE bc.BeerName=ANY
  (SELECT b2.BeerName FROM dbo.Beer AS b2);
 

See possible answers