Dealing with High Concurrency with Table Hints
Systems with a large number of requests on a critical database table are prone to blocking and slowness. We take a look at getting things done using T-SQL table hints.
2017-06-20
3,630 reads
Systems with a large number of requests on a critical database table are prone to blocking and slowness. We take a look at getting things done using T-SQL table hints.
2017-06-20
3,630 reads
With the data proliferation issues, a well-defined lifecycle for data retention is a growing demand.
2016-11-10
2,188 reads
There's built-in JSON support starting with SQL Server 2016. Does that mean we should all ditch XML and start using JSON? It depends mostly on the target of your data output processing.
2016-08-16
5,272 reads
What about database development? In most projects, developers aren’t focused on database development and for proper CI, the database version should keep neck to neck with the application builds.
2016-06-08
4,220 reads
One feature that I have been waiting for years! The new announcement around optimize...
Following on from my last post about Getting Started With KubeVirt & SQL Server,...
By DesertDBA
I haven’t posted in a while (well, not here at least since I’ve been...
Comments posted to this topic are about the item Refactoring SQL Code, which is...
Comments posted to this topic are about the item The Read Committed Snapshot Isolation...
Comments posted to this topic are about the item Working with JSON/JSONB Data in...
I am currently working with Sql Server 2022 and AdventureWorks database. First of all, let's set the "Read Committed Snapshot" to ON:
use master; go alter database AdventureWorks set read_committed_snapshot on with no_wait; goThen, from Session 1, I execute the following code:
--Session 1 use AdventureWorks; go create table ##t1 (id int, f1 varchar(10)); go insert into ##t1 values (1, 'A');From another session, called Session 2, I open a transaction and execute the following update:
--Session 2 use AdventureWorks; go begin tran; update ##t1 set f1 = 'B' where id = 1;Now, going back to Session 1, what happens if I execute this statement?
--Session 1 select f1 from ##t1 where id = 1;See possible answers