TSQL Challenge 76 - Identify the sequence of accounting transactions
The challenge is to identify the sequence of accounting transactions.
2012-02-20
1,628 reads
The challenge is to identify the sequence of accounting transactions.
2012-02-20
1,628 reads
The challenge is to find the Episode and Sequence based on interval.
2012-02-06
1,270 reads
The challenge is to create a query for a report that show expiring material
2012-01-23
923 reads
The challenge is to wrap the text by specified position.
2012-01-09
2,883 reads
This challenge invites you to solve a payroll challenge which requires to calculate the number of hours employee worked in a week.
2011-12-26
1,818 reads
Your task is to process the input table that contains several mangled words and try to 'un-mangle' them and validate them against a 'dictionary' table.
2011-12-12
1,395 reads
This challenge invites you to identify the longest sequence of alphabets from a string.
2011-11-28
976 reads
Your job is to write a TSQL query that returns the advertisements most relevant to each web page given in the source table.
2011-11-14
600 reads
This challenge invites you to Generate kaprekar kernel or series from numbers.
2011-10-31
880 reads
This challenge invites you to identify the largest sequence of alphabets from a string.
2011-10-17
935 reads
By Steve Jones
Superheroes and saints never make art. Only imperfect beings can make art because art...
One feature that I have been waiting for years! The new announcement around optimize...
Following on from my last post about Getting Started With KubeVirt & SQL Server,...
Comments posted to this topic are about the item The AI Bubble and the...
Hi, in a simple oledb source->derived column->oledb destination data flow, 2 of my...
hi, i noticed the sqlhealth extended event is on by default , and it...
I am currently working with Sql Server 2022 and AdventureWorks database. First of all, let's set the "Read Committed Snapshot" to ON:
use master; go alter database AdventureWorks set read_committed_snapshot on with no_wait; goThen, from Session 1, I execute the following code:
--Session 1 use AdventureWorks; go create table ##t1 (id int, f1 varchar(10)); go insert into ##t1 values (1, 'A');From another session, called Session 2, I open a transaction and execute the following update:
--Session 2 use AdventureWorks; go begin tran; update ##t1 set f1 = 'B' where id = 1;Now, going back to Session 1, what happens if I execute this statement?
--Session 1 select f1 from ##t1 where id = 1;See possible answers