Review of Review of SQL Server 2000 Administrators' Companion
Nice write up on the Admin Companion. Should you add it to your bookshelf? Frank offers his frank opinion.
2004-03-26
4,141 reads
Frank Kalis
Script to display permissions in a db
The script creates a stored procedure which lists all permissions on a given db on execution. Unlike other scripts it does not use a cursor. I have chosen the sp_* prefix as I have created it in master. Have fun!
2004-02-27
514 reads
An Introduction to Database Models
Frank returns this week with a good non academic overview of the different types of database models and some of the features/problems that are native to each.
2004-02-12
11,194 reads
Codd's Rules
Frank gives us his take on Codd's Rules. If you're new to databases, this is the core theory that resulted in the development of RDBMS. If you're more experienced with databases, maybe now is a good time to return to the rules to see how you're doing!
2003-12-10
20,468 reads
A Brief History of SQL
Frank has been part of our community for a while now, posting more than 1000 times (wow!) in our discussion area. He's decided to contribute more of his time by putting together an article that discusses how SQL has evolved.
2003-09-10
10,858 reads
Blogs
Identity Columns Can’t Be Updated: #SQLNewBlogger
By Steve Jones
I’m not sure I knew identity column values could not be updated. I ran...
Rolling Back a Broken Release
By Steve Jones
We had an interesting discussion about deployments in databases and how you go forward...
A bespoke reporting solution doesn’t have to cost the earth
By ChrisJenkins
You could be tolerating limited reporting because there isn’t an off the shelf solution...
Forums
Can someone please explain what happens?
I have mentioned this several times over several years. Can someone please help me...
SELECT COUNT(DISTINCT) returns null when nothing is found instead of 0
SELECT COUNT(DISTINCT Component) AS Found FROM tblComponents WHERE(Component NOT LIKE '%[a-z]%') AND(LTRIM(RTRIM(Component)) = 'GM13622')...
Remotely Engineer Fabric Lakehouse objects: The Fabric Modern Data Platform
Comments posted to this topic are about the item Remotely Engineer Fabric Lakehouse objects:...
Question of the Day
Creating JSON III
In a SQL Server 2025 table, called Beer, I have this data:
BeerIDBeerName 1Becks 2Fat Tire 3Mac n Jacks 4Alaskan Amber 8KirinI run this code:
SELECT JSON_OBJECTAGG(
BeerID: BeerName )
FROM beer;
What are the results? See possible answers