Endi Zhupani is a university graduate from Tirana with a degree in Information Systems. He currently works for Pragmatic Software, a company in Tirana that develops transaction and operation management systems as web applications. Throughout his entire development experience, Q&A and blog posts from other developers have saved my day more times that he can count, so he thought he’d start giving back by writing about my work and solutions he has come up with for some interesting problems.

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Documenting databases

Open any book or article about database development and administration, and I can all but guarantee that you will find a section for database documentation that describes its importance,...

2017-01-11

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Blog Post

Tables can't be compared

"I am trying to compare two databases and xSQL Data Compare has marked all table pairs with a red X and the messages on the output window show something like [16:08:11]...

2017-01-11

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Blogs

Optimising Costs: Strategies for Efficient Cloud Resource Management

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Over time, I’ve realised that one of the hardest parts of cloud management isn’t...

Cost Visibility: Tracking and Analysing Your Cloud Spend

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One of the biggest challenges I’ve faced in cloud operations is maintaining clear visibility...

Whiling away an afternoon, thinking

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I come to Heathrow often. Today is likely somewhere close to 60 trips to...

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Forums

Fun with JSON II

By Steve Jones - SSC Editor

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Changing Data Types

By Steve Jones - SSC Editor

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Answering Questions On Dropped Columns

By Cláudio Silva

Comments posted to this topic are about the item Answering Questions On Dropped Columns

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Question of the Day

Fun with JSON II

I have some data in a table: 

CREATE TABLE #test_data
(
    id INT PRIMARY KEY,
    name VARCHAR(100),
    birth_date DATE
);

-- Step 2: Insert rows  
INSERT INTO #test_data
VALUES
(1, 'Olivia', '2025-01-05'),
(2, 'Emma', '2025-03-02'),
(3, 'Liam', '2025-11-15'),
(4, 'Noah', '2025-12-22');
If I run this query, how many rows are returned? 
SELECT t1.[key] AS row,
       t2.*
FROM OPENJSON(
     (
         SELECT t.* FROM #test_data AS t FOR JSON PATH
     )
             ) t1
    CROSS APPLY OPENJSON(t1.value) t2;

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