brikitt

BRIKitt is a new-age PropTech company revolutionizing the real estate industry through fractional investment. Our Integrated PropTech ecosystem seamlessly combines technological expertise with a deep understanding of real estate dynamics, empowering investors to transform their owned properties into lucrative income sources through innovative investment ideas.

With BRIKitt, fractional real estate investments are simplified to their essence. We handle all maintenance requirements, allowing you to enjoy the benefits hassle-free. Our mission is to redefine the concept of owning a holiday home, making it a smart and stress-free experience for our clients.

All authors

It seems we can’t find what you’re looking for. Perhaps searching can help.

Blogs

T-SQL Tuesday #192: What career risks have you taken?

By

I’m honored to be hosting T-SQL Tuesday — edition #192. For those who may...

AI: Blog a Day – Day 3: LLM Models – Open Source vs Closed Source

By

Continuing from Day 2 , we learned introduction on Generative AI and Agentic AI,...

How to Parameterize Fabric Linked Services in Azure Data Factory for Azure Devops Deployment

By

Quite the title, so let me set the stage first. You have an Azure...

Read the latest Blogs

Forums

how to write this query?

By water490

hi everyone I am not sure how to write the query that will produce...

Rollback vs. Roll Forward

By Steve Jones - SSC Editor

Comments posted to this topic are about the item Rollback vs. Roll Forward

Foreign Keys - Foes or Friend?

By utsav

Comments posted to this topic are about the item Foreign Keys - Foes or...

Visit the forum

Question of the Day

Fun with JSON I

I have some data in a table: 

CREATE TABLE #test_data
(
    id INT PRIMARY KEY,
    name VARCHAR(100),
    birth_date DATE
);

-- Step 2: Insert rows  
INSERT INTO #test_data
VALUES
(1, 'Olivia', '2025-01-05'),
(2, 'Emma', '2025-03-02'),
(3, 'Liam', '2025-11-15'),
(4, 'Noah', '2025-12-22');
If I run this query, how many rows are returned? 
SELECT *
FROM OPENJSON(
     (
         SELECT t.* FROM #test_data AS t FOR JSON PATH
     )
             ) t;

See possible answers