Brad McGehee

Brad M. McGehee is a MCSE+I, MCSD, and MCT (former) with a Bachelors’ degree in Economics and a Masters in Business Administration. Currently the Director of DBA Education for Red Gate Software, Brad is an accomplished Microsoft SQL Server MVP with over 13 years’ SQL Server experience, and over 6 years’ training experience.

Brad is a frequent speaker at SQL PASS, SQL Connections, SQLTeach, SQL Saturdays, TechFests, Code Camps, SQL Server user groups, and other industry seminars, where he shares his 13 years’ cumulative knowledge.

Brad was the founder of the popular community site SQL-Server-Performance.Com, and operated it from 2000 through 2006, where he wrote over one million words on SQL Server topics.

In 2008, Brad attended 16 conferences/user group events, presented 26 sessions, and had 1,402 people attend them.

A well-respected and trusted name in SQL Server literature, Brad is the author or co-author of more than 14 technical books and over 100 published articles. His most recent books include “How to Become an Exceptional DBA,” and “Brad's Sure Guide to SQL Server 2008: The Top Ten New Features for DBAs,” and “Mastering SQL Server Profiler.”

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SQLServerCentral Editorial

Is Your Server Vendor Providing the Quality, Innovation, and Support You Need?

We should get help from vendors, as well as support, but what about innovation? Today's guest editorial from Brad McGeHee asks if the third party tool vendors for SQL Server are doing enough to provide value for the cost of their tools.

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2009-10-06

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Question of the Day

The string_agg function

We create the following table and then insert some records in it: 

create table t1 (
   id int primary key,
   category char(1) not null,
   product varchar(50)
);

insert into t1 values
(1, 'A', 'Product 1'),
(2, 'A', 'Product 2'),
(3, 'A', 'Product 3'),
(4, 'B', 'Product 4'),
(5, 'B', 'Product 5');
What happens if we execute the following query in both Sql Server and PostgreSQL? 
select id, 
category, 
string_agg(product, ';')
                 over (partition by category order by id
                 rows between unbounded preceding and unbounded following) as stragg
from t1;

See possible answers