Is my SQL Server Pre-Release?
I get to work with a lot of different clients and client environments and like many companies they are often...
2010-08-19
341 reads
I get to work with a lot of different clients and client environments and like many companies they are often...
2010-08-19
341 reads
With everyone geared up for SQL Cruise I’m surprised we can air this video but since we kicked it off...
2010-08-19
353 reads
This week it's all about speed. Many thing in life are drive n by how fast we can get them...
2010-08-19
362 reads
Check out our latest book on Amazon. It’s not for sales yet, but just seeing the title up there is...
2010-08-19
346 reads
Ok folks, the video from SQL Saturday 40 is finally up. Thanks to the sponsors who helped foot the bill...
2010-08-19
322 reads
Well SQL Saturday here in South Florida was QUITE an event this past weekend. We had over 400+ attendees and...
2010-08-19
469 reads
One of the most common questions I get from folks during out quickstart engagements is around a new service in...
2010-08-19
467 reads
This is long overdue and goes out to my buddies from the SSAS Class I taught late last year. Two...
2010-08-19
383 reads
Some great SQL Lunch sessions are coming up. Some from Pragmatic folks and some from other great speakers and community...
2010-08-19
366 reads
Some great SQL Lunch sessions are coming up. Some from Pragmatic folks and some from other great speakers and community...
2010-08-19
385 reads
One thing I’ve always loved about the Scooby-Doo cartoon is that he never solved...
By Kevin3NF
Flexibility and Scale at the Database Level When SQL Server 2012 introduced Availability Groups...
Setting page visibility and the active page are often overlooked last steps when publishing...
Comments posted to this topic are about the item Password Guidance
Comments posted to this topic are about the item Using table variables in T-SQL
I am trying to check out elastic query between two test instances we have...
What happens if you run the following code in SQL Server 2022+?
declare @t1 table (id int); insert into @t1 (id) values (NULL), (1), (2), (3); select count(*) from @t1 where @t1.id is distinct from NULL;See possible answers