Do you get tired of reviewing each SQL Agent notifications nightly to determine which SQL Agent jobs failed? Is there a significant number of SQL Agent job notifications that it takes a while to review each? Here is an alternative that allows you to have a single email report of all job failures.
2002-09-17
11,735 reads
New columnist Gregory Larsen used to not care what his objects were called until recently when he began to become concerned with the system generated constraint names. This short article tells you why.
2002-08-16
7,155 reads
This stored procedure produces a report of record counts for every table on your server. The record count report is organized by database, and table name.
2002-05-16
652 reads
By Steve Jones
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By Chris Yates
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Presenting you with an updated version of our sp_snapshot procedure, allowing you to easily...
Just saw the "Azure Extension for SQL Server" Does anyone has experience with it?...
I've noticed several instances of what looks like a recursive insert with the format:...
Comments posted to this topic are about the item Cleaning Up the Cloud
I have a table with this data:
TravelLogID CityID StartDate EndDate 1 1 2025-01-01 2025-01-06 2 2 2025-01-01 2025-01-06 3 3 2025-01-01 2025-01-06 4 4 2025-01-01 2025-01-06 5 5 2025-01-01 2025-01-06I run this code:
SELECT IDENT_CURRENT('TravelLog')
I get the value 5 back. Now I do this:
SET IDENTITY_INSERT dbo.TravelLog ON
INSERT dbo.TravelLog
(
TravelLogID,
CityID,
StartDate,
EndDate
)
VALUES
(25, 5, '2025-09-12', '2025-09-17')
SET IDENTITY_INSERT dbo.TravelLog OFF
I now run this code.
DBCC CHECKIDENT(TravelLog)
GO
INSERT dbo.TravelLog
(
CityID,
StartDate,
EndDate
)
VALUES
(4, '2025-10-14', '2025-10-17')
GO
What is the value for TravelLogID for the row I inserted for CityID 4 and dates starting on 14 Oct 2025?
See possible answers