Bradley Schacht is a Data Platform Solution Architect on the state and local government team with Microsoft based in Jacksonville, FL. He has co-authored 3 SQL Server books including "SQL Server 2014 Professional Admin". As a former consultant and trainer, he uses his experience on many parts of the Microsoft BI and data platform to help customers deliver the best possible solutions. Bradley frequently presents at community events around the country. He is a contributor to sites such as SQLServerCentral.com and an active member of the Jacksonville SQL Server User Group (JSSUG).

All authors

All authors

Blogs

Finding and Updating Duplicate IDs: #SQLNewBlogger

By

Finding duplicates was an interview question for me years ago, and I’ve never forgotten...

Optimising Costs: Strategies for Efficient Cloud Resource Management

By

Over time, I’ve realised that one of the hardest parts of cloud management isn’t...

Cost Visibility: Tracking and Analysing Your Cloud Spend

By

One of the biggest challenges I’ve faced in cloud operations is maintaining clear visibility...

Read the latest Blogs

Forums

Fun with JSON II

By Steve Jones - SSC Editor

Comments posted to this topic are about the item Fun with JSON II

Changing Data Types

By Steve Jones - SSC Editor

Comments posted to this topic are about the item Changing Data Types

Answering Questions On Dropped Columns

By Cláudio Silva

Comments posted to this topic are about the item Answering Questions On Dropped Columns

Visit the forum

Question of the Day

Fun with JSON II

I have some data in a table: 

CREATE TABLE #test_data
(
    id INT PRIMARY KEY,
    name VARCHAR(100),
    birth_date DATE
);

-- Step 2: Insert rows  
INSERT INTO #test_data
VALUES
(1, 'Olivia', '2025-01-05'),
(2, 'Emma', '2025-03-02'),
(3, 'Liam', '2025-11-15'),
(4, 'Noah', '2025-12-22');
If I run this query, how many rows are returned? 
SELECT t1.[key] AS row,
       t2.*
FROM OPENJSON(
     (
         SELECT t.* FROM #test_data AS t FOR JSON PATH
     )
             ) t1
    CROSS APPLY OPENJSON(t1.value) t2;

See possible answers