Split

,

Split function accepts a string and a delimeter.
It divides the string in words by the delimeter.

CREATE FUNCTION dbo.Split (@vcDelimitedString 	varchar(8000),
			   @vcDelimiter		varchar(1))

/**************************************************************************
DESCRIPTION: Accepts a delimited string and splits it at the specified
		delimiter points.  Returns the individual items as a table data
		type with the ElementID field as the array index and the Element
		field as the data

PARAMETERS:
		@vcDelimitedString	- The string to be split
		@vcDelimiter		- String containing the delimiter where
					  delimited string should be split

RETURNS:
		Table data type containing array of strings that were split with
		the delimiters removed from the source string

USAGE:
		SELECT ElementID, Element FROM Split('11111,22222,3333', ',') 
		ORDER BY ElementID

AUTHOR:	Karen Gayda

DATE: 	05/31/2001

MODIFICATION HISTORY:
	WHO		DATE		DESCRIPTION
	---		----------	---------------------------------------------------

***************************************************************************/
RETURNS @tblArray TABLE 
   (
	ElementID	smallint	IDENTITY(1,1),  --Array index
   	Element		varchar(1000)			--Array element contents
   )
AS
BEGIN

	DECLARE 
		@siIndex	smallint,
		@siStart	smallint,
		@siDelSize	smallint

	
	SET QUOTED_IDENTIFIER ON

	SET @siDelSize	= LEN(@vcDelimiter)

	--loop through source string and add elements to destination table array

	WHILE LEN(@vcDelimitedString) > 0
	BEGIN
		SET @siIndex = CHARINDEX(@vcDelimiter, @vcDelimitedString)
		IF @siIndex = 0
		BEGIN
			INSERT INTO @tblArray VALUES(@vcDelimitedString)
			BREAK
		END
		ELSE
		BEGIN
			INSERT INTO @tblArray VALUES(SUBSTRING(@vcDelimitedString, 1,@siIndex - 1))
			SET @siStart = @siIndex + @siDelSize
			SET @vcDelimitedString = SUBSTRING(@vcDelimitedString, @siStart , LEN(@vcDelimitedString) - @siStart + 1)
		END
	END
	
	RETURN
END

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