Viewing 4 posts - 1 through 5 (of 5 total)
Thanks for all your help! I really appreciate it.
March 16, 2010 at 11:26 am
I have one column with duplicate entries:
Column1
A
A
B
B
B
C
I'd like to create a new column that generates a counter within each duplicate record.
Column1 NewColumn
A ...
March 15, 2010 at 3:16 pm
This works!!! Thanks. I have another question:
Do you know how to pivot transform the data so that it looks like this:
Unpivoted Data:
Column1 Column2 Column3
A ...
March 15, 2010 at 11:39 am
Sorry I got column2 data wrong. I'm actually trying to get the following data values in Column2:
Column1 Column2
A ...
March 14, 2010 at 9:36 pm
Viewing 4 posts - 1 through 5 (of 5 total)