Viewing 15 posts - 13,741 through 13,755 (of 13,870 total)
Something like this?
select t.transporter_name, a.state_id
from transporters t left outer join association a on
t.transporter_id = a.transporter_id
where state_id = 101 or state_id is null
September 10, 2004 at 12:36 am
Perhaps you could run Profiler to check the SQL Server side of the equation? Otherwise, I'm running out of ideas.
Good luck
Phil
September 9, 2004 at 11:20 pm
So do you know at what stage in the process that the conversion is failing for these records?
I'm thinking it could be
a) Something in the logic of the conversion program...
September 9, 2004 at 11:06 pm
So you've got everything you can find on your server set to US format and you're still getting d/m/y date format problems from somewhere?
September 9, 2004 at 10:42 pm
So are you trying to make your SQL Server 'pretend' it is American? Don't know whether this will work, but you might try changing the control panel/regional options on...
September 9, 2004 at 10:16 pm
Hi Ed
If, for a particular record in 'organization', a related record does not exist in the 'totals' table, all of the fields retrieved from the totals table will be NULL.
So...
September 8, 2004 at 6:03 pm
In general, for readability ...
'On' should be used for joins between tables:
select * from tablea a inner join tableb b
on a.id = b.id
etc
'Where' should be used to filter the results...
September 8, 2004 at 12:33 am
Are you looking for all the combinations -
PRIM1 | A | B
---------------------
1 A1 B1
1 A1 B2
1 A1 B3
1 A2 B1
1 A2 B2
1 A2 B3
From your post, I'm guessing not....
September 2, 2004 at 11:55 pm
Agree with you Joseph - same has happened to me several times, on the longer, more time-consuming posts of course. There must be a way round this that doesn't...
September 2, 2004 at 9:15 pm
Something like this should get you close:
SELECT S.record_count,
max(T.trip_id),
S.compart_no,
T.boat_id,
T.boat_type,
S.recordor_id,
S.record_type,...
September 2, 2004 at 6:25 pm
Have you posted this in the wrong forum, or is there some hidden T-SQL problem?
September 2, 2004 at 12:15 am
Use the isnull() function. Try this example:
declare @var1 integer, @var2 integer
set @var1 = null
set @var2 = 25
select isnull(@var1,0) as var1, isnull(@var2,0) as var2
Cheers
Phil
September 1, 2004 at 10:12 pm
Here's another stupid way:
SELECT DATENAME(month, @month * 28)
-- where @month contains an integer between 1 and 12.
Can't see any more obvious way. It would perhaps be more elegant to...
September 1, 2004 at 10:07 pm
Hi Russell - so what, exactly, are you looking for?
1) Are you looking for a way of randomly selecting a sample % of records from an overall population?
2)...
August 31, 2004 at 10:06 pm
Wow! How accurate do you need to be? ![]()
The Money datatype in SQL Server helpfully rounds to 4dp, so that's possibly where things...
August 27, 2004 at 1:26 am
Viewing 15 posts - 13,741 through 13,755 (of 13,870 total)