For starters, MAX ([Date_Started]), MAX([Time_Started]) needs to be modified to MAX([Date_Started]) + [Time_Started]).  The actual calculation will depend on the data types of the 2 fields.

Also, be aware that UNION will be much slower that UNION ALL, as it will only return a DISTINCT result, which requires an additional sort operation

You could find all of the columns sys.columns, but there is no way to know which ones are alligned.

So, as far as I know, you have to do it manually.

select...

As a perf update, you can use the following code for extracting Title.

C.x.value( '(title/text())[1]', 'varchar(100)' )

I am not an XML expert, but this was a tip that...

I seem to recall a rule in place that if 3 posts for the same user are flagged as spam, the user automatically gets disabled.  Is that rule still in...

Ah, I missed the fact that you are using SQL 2012.

The other option is to just force the AnchorDate to DTO (knowing that SQL assumes that it is UTC)

            
February 22, 2022 at 3:14 pm
            
#3986951

            
            
                                                
        

You can also use the AT TIME ZONE functionality for the test

/*
Queries tested on SQL Server 2012 with default timezone of Eastern Standard Time.
*/

DECLARE @ComparisonDateAsDTO datetimeoffset(7) =...

This is easily achieved with a cross-tab query

CREATE TABLE #Animal (ID int, Animal varchar(20), Number int, [Year] int);

INSERT INTO #Animal ( ID, Animal, Number, [Year] )
VALUES (...

This is very easy to achieve using the LAG function

Depending on the actual data in the xml as well as the xml structure of the various records, you find storage improvements by storing the xml as [n]varchar(max).

Here is a link to a post by Drew Allen https://www.sqlservercentral.com/forums/reply/2031829 which covers islands

You have not provided any usable data or a base query to be able to test against.

The following code should get you moving in the right direction

WITH...

 

When assigning values to a string data...

• This reply was modified 3 years, 10 months ago by DesNorton. Reason: Fixed copy/paste error (Thanks kaj)

The following code should do the trick

SUBSTRING(part, LEN(part) - CHARINDEX('-', REVERSE(part)) -1, 2)

HAVING SUM([FileSize]) > 104857600 - This returns 15 ROWS

What is the value of [SumOfFileSize] for the 15 rows? How many of them are greater than 10485760000?

Based on...