Viewing 15 posts - 1,096 through 1,110 (of 2,007 total)
IowaDave (1/5/2012)
I have lost many of my add-ons that I loved because they were not compatible with the new version.
One of the reasons I stopped using firefox. . .
There is...
January 5, 2012 at 7:28 am
If you did mean that all you want is the "root" and the last leaf, try this instead: -
BEGIN TRAN
CREATE TABLE #Modules ([ModuleId] INT, [ModuleName] VARCHAR(50) NOT NULL, [ParentId] INT...
January 5, 2012 at 4:56 am
vijay.s (1/5/2012)
@CadavreYour query is also returning the same result as mentioned above.
I just want to lowest parent (nth parent) and highest child.
Oh, misread the requirements.
CREATE TABLE #Modules ([ModuleId] INT, [ModuleName]...
January 5, 2012 at 4:45 am
rajeev_vandakar-782919 (1/5/2012)
Thank you for reply.
I tried this way to get member_id, member_name, age also in the same row, but failed.
I need to get all the...
January 5, 2012 at 4:20 am
CREATE TABLE #Modules ([ModuleId] INT, [ModuleName] VARCHAR(50) NOT NULL, [ParentId] INT NULL)
INSERT INTO #Modules
SELECT 1, 'Master', NULL
UNION ALL SELECT 2, 'List', 1
UNION ALL SELECT 3, 'EmployeeList', 2
UNION ALL SELECT 4,...
January 5, 2012 at 4:14 am
This article contains an explanation of the method used[/url].
BEGIN TRAN
--Sample data
CREATE TABLE employee_master (emp_id INT PRIMARY KEY, emp_name VARCHAR(4), dob DATETIME,
salary INT, join_date DATETIME)
INSERT INTO employee_master
SELECT 1, 'aaaa', '1976-03-01',...
January 5, 2012 at 2:15 am
January 5, 2012 at 1:46 am
SQLKnowItAll (1/4/2012)
Thanks for that, but what I am really trying to get at in this post is not an actual delimited...
January 5, 2012 at 1:37 am
January 4, 2012 at 10:07 am
andyman123456 (1/4/2012)
do we need to buy client access licences just to access cubes via excel ?
That depends on how you're licensing SQL Server. Read the links I provided.
January 4, 2012 at 7:30 am
andyman123456 (1/4/2012)
January 4, 2012 at 6:46 am
What license do you have?
http://www.sqlservercentral.com/blogs/pearlknows/2011/01/24/microsoft-sql-server-licensing-for-dummies/%5B/url%5D
January 4, 2012 at 6:37 am
Having some difficulty understanding what you're after, so here's my best guess.
BEGIN TRAN
CREATE TABLE [dbo].[groupsAssociation](
[Id] [int] IDENTITY(1,1) NOT NULL,
...
January 3, 2012 at 3:41 am
Totally untested, I'm not at my desk any more.
using Microsoft.SqlServer.Server;
using System.Data.SqlTypes;
using System;
using System.IO;
namespace XMLWriter
{
public class XMLWriter
{
...
December 21, 2011 at 9:54 am
SQL Guy 1 (12/21/2011)
I could...
December 21, 2011 at 9:31 am
Viewing 15 posts - 1,096 through 1,110 (of 2,007 total)