Viewing 15 posts - 1,891 through 1,905 (of 5,504 total)
How about sending the last few hundred (?) posts to DiscoveryChannel? They might be able to make a few stories out of it... 😀
Very entertaining for an ESL who has...
February 18, 2011 at 4:58 pm
Brandie Tarvin (2/18/2011)
And I forgot...
February 18, 2011 at 6:59 am
christophe.bernard 47659 (2/18/2011)
thanks for your time and your knowledge ..that's work ..yes 🙂 🙂 !
I'm a beginner with t sql and i'm not sure to understand your code...
February 18, 2011 at 3:55 am
Please don't start a new thread if you have additional information to a question already posted.
Original post including a first reply can be here
February 17, 2011 at 2:37 pm
GSquared (2/17/2011)
...Yes, at camelsexchange.com. :w00t:
Must be a pain for the camel. (They still use bricks for it, right?) :pinch::crying:
February 17, 2011 at 1:20 pm
I'd use either a LEFT OUTER JOIN or a NOT EXISTS subqry.
February 17, 2011 at 12:01 pm
Brandie Tarvin (2/17/2011)
What is the effect of building a non-clustered index over a clustered index?
The table already uses CoverageKey and Effective (both ASC) as it's clustered index. Include only works...
February 17, 2011 at 11:30 am
I'd rather go with
SELECT
x.i.value('(@parentStructId)[1]','int') AS ParentStructID,
x.i.value('(@family)[1]','int') AS Family,
x.i.value('(@subFamily)[1]','int') AS SubFamily
FROM @xmlFile.nodes('/FamilyAndSubFamily/myStruct') as x(i);
It performs better than the x.i.query('.').value approach. (see execution plan and statistics on a larger data volume)
February 17, 2011 at 11:07 am
LutzM (2/16/2011)
Examples:
Product 2 is available until 2-8-2011. How do you know it's not available after that?
Product 5 is not available starting from 2-9-2011....
February 16, 2011 at 2:59 pm
How do you come to this conclusion?
Examples:
Product 2 is available until 2-8-2011. How do you know it's not available after that?
Product 5 is not available starting from 2-9-2011. How...
February 16, 2011 at 1:33 pm
Without any more details (like table def, sample data, expected result and the like) it's hard to tell.
My guess would be there are more than one rows with nome ='Albertino...
February 16, 2011 at 1:23 pm
Pouliot Philippe (2/16/2011)
Or i must will go with Exam 70-432(Sql Server 2008)
What do you think about that...
February 16, 2011 at 1:18 pm
Rich Yarger (2/15/2011)
February 16, 2011 at 12:17 pm
GilaMonster (2/15/2011)
LutzM (2/15/2011)
GilaMonster (2/15/2011)
In your example index 1 is redundant (the columns match exactly a left-based subset of another index), index 2 is not.
Wouldn't index 1 be used if a...
February 16, 2011 at 11:44 am
Viewing 15 posts - 1,891 through 1,905 (of 5,504 total)