Viewing 15 posts - 2,806 through 2,820 (of 5,356 total)
You mean an XP?
Well, actually our developers who code app to work with the data from one of our bank partners is bound by the bank to use VB5 and...
January 15, 2004 at 12:51 pm
Yes, I also thought of this, but IIRC you need to be on SQL 2k to have it available, right? ![]()
January 15, 2004 at 12:33 pm
OK, I'll try ![]()
It is this what you are looking for?
SELECT h.ItemNo, l.MaxOH - SUM(ISNULL(p.PQty,0)) AS QtyReq, 'Rush - 4...
January 15, 2004 at 7:55 am
or
SELECT SERVERPROPERTY ('productversion')
SELECT SERVERPROPERTY ('productlevel')
SELECT SERVERPROPERTY ('edition')
January 15, 2004 at 7:41 am
Hmph,...it seems that my laptop is too fast compared to your computer
![]()
January 15, 2004 at 6:35 am
As for the CreateDate of a row, simply put a DEFAULT of GETDATE() on the column.
As for the LastChangeDate I guess you will have to write triggers
January 15, 2004 at 6:15 am
I know! I'm a silent follower of the SQL2k mailing list ![]()
Formatting works somehow, but isn't that user-friendly.
Let's hope for the best!
January 15, 2004 at 6:08 am
Strike!
SELECT
settings
FROM
thisStupidWebThing
WHERE
easeOfUse IS NOT NULL
That's really sad, I really appreciate following your mails.
January 15, 2004 at 4:09 am
SET QUOTED_IDENTIFIER OFF
GO
SET ANSI_NULLS OFF
GO
DECLARE @i INT
DECLARE @vNIL INT
DECLARE @szString VARCHAR(255)
SET @i=35
SET @szString=''
WHILE (@i>0)
BEGIN
SET @vNIL=@i % 16
SET @i=@i /16
IF @vNIL>9
SET @szString=char(55+@vNIL)+@szString
ELSE
SET @szString=char(48+@vNIL)+@szString
END
SELECT @szString
GO
SET QUOTED_IDENTIFIER OFF
GO
SET...
January 15, 2004 at 3:04 am
I agree that a trigger won't work.
The idea to schedule a job is good, but I wouldn't run this every morning.
What happens when someone gets 18 on a saturday...
January 15, 2004 at 2:29 am
sorry, replace print.... by select @a, @GradesCount
January 15, 2004 at 2:27 am
declare @a int
declare @GradesCount int
SELECT TOP 1 @a = StudentID, @GradeCount = Count(*) FROM Results GROUP BY StudentID ORDER BY Count(*) DESC
print @a + ' - ' + @GradesCount
should work
January 15, 2004 at 2:24 am
would
SELECT TOP 1 StudentID, Count(*) AS No_of_Grades FROM Results GROUP BY StudentID ORDER BY No_of_Grades DESC
help
January 15, 2004 at 1:55 am
Please avoid double postings. See Allen Cui's answer here
http://www.sqlservercentral.com/forums/shwmessage.aspx?forumid=5&messageid=95240
January 15, 2004 at 1:19 am
This might serve as a starting point
SELECT
a.id AS Tableid, a.Name AS TableName, b.name AS colName, b.colid AS colId,
d.name AS constraintname, d.xtype AS constrainttype , e.name
FROM
((((sysobjects a INNER JOIN syscolumns b...
January 15, 2004 at 1:16 am
Viewing 15 posts - 2,806 through 2,820 (of 5,356 total)