What's the Length?

  • Comments posted to this topic are about the item What's the Length?

  • Interesting question but an easy one for me only because I remembered that the default value of the max length of a string is 4000. I have to admit that I needed 5 minutes to be sure of the correct value ( 3996 ) in this case.

    The solution you provided is interesting and useful at least according to me. I am sure I would need 15 minutes to find it as I have not used this function since the release of SQL Server 2008 a long time ago ... ( pure T-SQL is not my preferred topic , but I will do some tests in the next days ).

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  • Great question to start the week. Thanks!

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  • The MAX lengths will get you every time when it comes to lengths and joining to them. Interesting question.

  • I would actually change the variable definition.

    DECLARE

    @max-2 AS NVARCHAR(MAX) = ''

    , @Var AS NVARCHAR(MAX) = 'ABCabc123';

    SELECT

    @max-2 = REPLICATE(@Var, 445);

    SELECT

    CASE WHEN LEN(@Max) = LEN(@Var) * 445 THEN 'Simple math'

    ELSE 'It''s complicated'

    END;

    This is a common problem when creating long dynamic sql strings. I hope that people learn from this question.

    Luis C.
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    Are you seriously taking the advice and code from someone from the internet without testing it? Do you at least understand it? Or can it easily kill your server?

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  • Fun questions, thanks Umer Akram.


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  • Interesting question. I learned something, b/c I don't use REPLICATE() for long strings.

    The explanation from BOL is quite specific:

    If string_expression is not of type varchar(max) or nvarchar(max), REPLICATE truncates the return value at 8,000 bytes. To return values greater than 8,000 bytes, string_expression must be explicitly cast to the appropriate large-value data type.

    Rich

  • A really interesting question , thanks Umer . But just simple complicated? 😉

    DECLARE

    @max-2 AS NVARCHAR(MAX) = ''

    , @Var AS VARCHAR(4000) = 'ABCabc123';-- Varchar instead Nvarchar --

    SET @max-2 = REPLICATE(@Var, 445);

    SELECT LEN(@Max) as LenMax, LEN(@Var) * 445 as LenVar,

    DATALENGTH(@Max) as DataLenMax, DATALENGTH(@Var) * 445 as DataLenVar;

    Ref.: https://msdn.microsoft.com/en-us/library/ms174383.aspx

  • Nice question, thanks.

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