October 7, 2015 at 6:03 am
Hello,
who can I use a variable like the followig
set @MAG3 = '<> 0'
or
set @MAG3 = '= 0'
for the following where condition
where patindex('%;' + Mitarbeiter + ';%' , @MAG2) <> 0
I like to change the <> 0 Parameter but
where patindex('%;' + Mitarbeiter + ';%' , @MAG2) @MAG3
don`t work.
Thank for help.
Olaf
October 7, 2015 at 6:10 am
orenk (10/7/2015)
Hello,who can I use a variable like the followig
set @MAG3 = '<> 0'
or
set @MAG3 = '= 0'
for the following where condition
where patindex('%;' + Mitarbeiter + ';%' , @MAG2) <> 0
I like to change the <> 0 Parameter but
where patindex('%;' + Mitarbeiter + ';%' , @MAG2) @MAG3
don`t work.
Thank for help.
Olaf
No, that's not going to work. Can you take a bit of time to explain the logic you are trying to achieve? There will be another way to achieve it, I'm sure.
October 7, 2015 at 6:29 am
Hello,
I have in my select a column called "Mitarbeiter". I like to search for Mitarbeiter in ('SB','MS','BE') or Mitarbeiter not in ('SB','MS','BE')
The 'IN' or 'NOT IN' I want to change via a variable. (For SQL Server Reports)
so I come to the patindex and the change between <>0 and =0
But how to change it?
Olaf
October 7, 2015 at 6:45 am
orenk (10/7/2015)
Hello,I have in my select a column called "Mitarbeiter". I like to search for Mitarbeiter in ('SB','MS','BE') or Mitarbeiter not in ('SB','MS','BE')
The 'IN' or 'NOT IN' I want to change via a variable. (For SQL Server Reports)
so I come to the patindex and the change between <>0 and =0
But how to change it?
Olaf
There's a simple way to do this:
WHERE (@Var3 = 'IN' AND Mitarbeiter IN ('SB','MS','BE'))
OR (@Var3 = 'NOT IN' AND Mitarbeiter NOT IN ('SB','MS','BE'))
It's called a "Catch-all" query and has known limitations. Gail Shaw has a good account of those limitations here[/url].
For fast, accurate and documented assistance in answering your questions, please read this article.
Understanding and using APPLY, (I) and (II) Paul White
Hidden RBAR: Triangular Joins / The "Numbers" or "Tally" Table: What it is and how it replaces a loop Jeff Moden
October 7, 2015 at 6:58 am
That works.
Thanks a lot. :satisfied:
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