Sum values in XML child nodes

  • From the sample here:

    http://blogs.msdn.com/b/simonince/archive/2009/04/24/flattening-xml-data-in-sql-server.aspx

    How would I sum the Ages of Simon and Peter?

    CREATE TABLE XmlSourceTable

    (

    RecordId INT IDENTITY(1,1) NOT NULL PRIMARY KEY,

    XmlData XML NOT NULL

    )

    GO

    XmlData = '

    <?xml version="1.0" ?>

    <Root>

    <Person>

    <Name>Simon</Name>

    <Age>20</Age>

    <Skills>

    <Skill>Cooking</Skill>

    <Skill>Cleaning</Skill>

    </Skills>

    </Person>

    <Person>

    <Name>Peter</Name>

    <Age>21</Age>

    <Skills>

    <Skill>Ironing</Skill>

    </Skills>

    </Person>

    </Root>'

    INSERT INTO XmlSourceTable(XmlData)

    SELECT *

    FROM OPENROWSET(

    BULK 'C:\XmlSource.xml', SINGLE_BLOB)

    AS ImportSource

    GO

    SELECT

    pref.value('(Name/text())[1]', 'varchar(50)') as PersonName,

    pref.value('(Age/text())[1]', 'int') as PersonAge,

    pref.query('Skills') as PersonSkills

    FROM

    XmlSourceTable CROSS APPLY

    XmlData.nodes('/Root/Person') AS People(pref)

    GO

  • Not sure exactly if this is what you're after but maybe it'll help:

    DECLARE @XmlData XML = '

    <Root>

    <Person>

    <Name>Simon</Name>

    <Age>20</Age>

    <Skills>

    <Skill>Cooking</Skill>

    <Skill>Cleaning</Skill>

    </Skills>

    </Person>

    <Person>

    <Name>Peter</Name>

    <Age>21</Age>

    <Skills>

    <Skill>Ironing</Skill>

    </Skills>

    </Person>

    </Root>'

    SELECT [Simon's Age]=x.value('(/Root/Person/Age)[1]', 'INT')

    ,[Peter's Age]=x.value('(/Root/Person/Age)[2]', 'INT')

    FROM (SELECT @XmlData) a(x)


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