String manipulation

Question

String manipulation

mabud_ncc

Valued Member

Points: 53
More actions
February 26, 2010 at 1:30 am

#217271

Hi,
I want to replace some characters from a string with some other characters like following
declare @pname varchar(255)
set @pname='This iŠ a tËšt nãmÉ'
select
(replace(replace(replace(replace(replace(replace(replace(replace(replace(replace(replace(replace(replace(replace(replace
(replace(replace(replace(replace(replace(replace(replace(replace(replace(replace(replace(replace(replace(replace(replace
(replace (replace (replace(replace(replace(replace (replace (replace(replace(replace(replace (replace (replace(replace
(replace(replace (replace (replace(replace(replace(replace (replace (replace(replace(replace(replace (replace (replace(replace
(replace(replace (replace (replace(replace(replace(replace (replace (replace(replace(replace(replace (replace (replace(replace
(replace(replace (replace (replace(replace(replace(replace (replace (replace(replace(replace(replace (replace (replace(replace
(replace(replace (replace (replace(replace(replace(replace (replace (replace(replace(replace(replace(replace(replace
(@pname,'Š','S'),'Œ','O'),'Ž','Z'),'š','s'),'œ','o'),'ž','z'),'Ÿ','Y'),'¥','Y'),'µ','u'),'À','A'),'Á','A'),'Â','A'),'Ã','A'),'Ä','A'),'Å','A'),
'Æ','A'),'Ç','C'),'È','E'),'É','E'),'Ê','E'),'Ë','E'),'Ì','I'),'Í','I'),'Î','I'),'Ï','I'),'Ð','D'),'Ñ','N'),'Ò','O'),'Ó','O'),'Ô','O'),'Õ','O'),
'Ö','O'),'Ø','O'),'Ù','U'),'Ú','U'),'Û','U'),'Ü','U'),'Ý','Y'),'ß','s'),'à','a'),'á','a'),'â','a'),'ã','a'),'ä','a'),'å','a'),'æ','a'),'ç','c'),
'è','e'),'é','e'),'ê','e'),'ë','e'),'ì','i'),'í','i'),'î','i'),'ï','i'),'ð','o'),'ñ','n'),'ò','o'),'ó','o'),'ô','o'),'õ','o'),'ö','o'),'ø','o'),
'ù','u'),'ú','u'),'û','u'),'ü','u'),'ý','Y'),'ÿ','Y'),
'!',' '),'@',' '),'#',' '),'$',' '),'%',' '),'^',' '),'&',' '),'*',' '),'(',' '),')',' '),'{',' '),'}',' '),'[',' '),']',' '),'|',' '),'\',' '),
':',' '),';',' '),'<',' '),'>',' '),'.',' '),'~',' '),'?',' '),'/',' '),'-',' '),'+',' '),'=',' '),'`',' '),'_',' '),',',' '),'"',' '),'''',' '),
'€',' '),'£','')))
This way , the performance is slower as it contains nested function so many times.
does anyone have any better idea to do that?
thanks in advanced

Viewing 6 posts - 1 through 5 (of 5 total)

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LutzM SSC Guru Points: 107049 More actions · Answer 1

I would use a table to store the character value and the substitute.

Step two would be the replacement by calling the REPLACE function for each entry in the table and assign the result to the same variable each time.

Usually, you could use @pname in the SELECT statement but I decided to use a separate variable for demonstration purposes (old and new value).

DECLARE @pname VARCHAR(255)

DECLARE @cname VARCHAR(255)

SET @pname='This iŠ a tËšt nãmÉ'

SET @cname=@pname

CREATE TABLE #tbl ( c1 CHAR(1), c2 CHAR(1))

INSERT INTO #tbl

SELECT 'Š'AS c1, 'S' AS c2 UNION ALL

SELECT 'È','E' UNION ALL

SELECT 'É','E' UNION ALL

SELECT 'Ê','E' UNION ALL

SELECT 'Ë','E' UNION ALL

SELECT 'à','a' UNION ALL

SELECT 'á','a' UNION ALL

SELECT 'â','a' UNION ALL

SELECT 'ã','a' UNION ALL

SELECT 'ä','a' UNION ALL

SELECT 'å','a'

SELECT @cname= REPLACE(@cname,c1,c2)

FROM #tbl

SELECT @pname AS 'BEFORE',@cname AS 'AFTER'

Lutz
A pessimist is an optimist with experience.

How to get fast answers to your question[/url]
How to post performance related questions[/url]
Links for Tally Table [/url] , Cross Tabs [/url] and Dynamic Cross Tabs [/url], Delimited Split Function[/url]

HowardW One Orange Chip Points: 29109 More actions · Answer 2

A tally table approach may be faster.

E.g. create a tally table as in this article:

http://www.sqlservercentral.com/articles/T-SQL/62867/

Create a lookup table for the find and replace strings:

CREATE TABLE Replace_Lookup (Find CHAR(1) PRIMARY KEY , [Replace] CHAR(1))

INSERT INTO Replace_Lookup

SELECT 'Š' AS find,'s' AS [REPLACE]

UNION ALL

SELECT 'Ë' AS find,'e' AS [REPLACE]

UNION ALL

SELECT 'ã' AS find,'a' AS [REPLACE]

UNION ALL

SELECT 'É' AS find,'e' AS [REPLACE]

UNION ALL

SELECT 'š' AS find,'s' AS [REPLACE]

and then use something like the below to replace all the chars:

declare

@pName varchar(255), @Replaced varchar(255)

Select @Replaced = '',@pName= 'This iŠ a tËšt nãmÉ'

SELECT @Replaced = @Replaced + ISNULL(Replace_Lookup.Replace,SUBSTRING(@pName,N,1))

FROM Tally

LEFT JOIN Replace_Lookup ON Replace_Lookup.Find=SUBSTRING(@pName,N,1)

WHERE N <= DATALENGTH(@pName)

SELECT @Replaced

However, a CLR solution is the best approach for this type of string manipulation

matzer SSCrazy Eights Points: 9727 More actions · Answer 3

Be careful. Depending on the collation being used you can get very odd results when comparing characters. For instance, I am using collation Latin1_General_CI_AS and the insertions into table Replace_Lookup fail because of a primary key constraint ('Ë' = 'É'). Use a binary comparison by using the COLLATE clause (i.e. REPLACE(@cname,c1 COLLATE Latin1_GENERAL_BIN,c2) or compare characters by their Ascii value (using function ASCII).

Check out the result of this script to see which character are equal in a given collation:

with Tally as

(

select top 256

number - 1 N

from

master..spt_values

where

type = 'P'

)

select

t1.N, char(t1.N), t2.N, char(t2.N)

from

Tally t1

cross join

Tally t2

where

t1.N <> t2.N

and char(t1.N) = char(t2.N)

order by

t1.N

Peter

Ramesh Saive SSC-Insane Points: 24275 More actions · Answer 4

Recently, I came across a similar post to which Jeff Moden has provided a WHILE loop based solution which beats the TALLY table solution.

Here is the post:

http://www.sqlservercentral.com/Forums/Topic860321-338-1.aspx

--Ramesh

Paul White SSC Guru Points: 150467 More actions · Answer 5

Ramesh Saive (2/26/2010)
Recently, I came across a similar post to which Jeff Moden has provided a WHILE loop based solution which beats the TALLY table solution. Here is the post:
http://www.sqlservercentral.com/Forums/Topic860321-338-1.aspx

...and I modified your solution in that thread to improve performance by a factor of more than twenty 😉

The REPLACE solution is fastest. A CLR solution (from previous experience and testing) is only slightly slower, but generally more flexible.

Paul

Paul White
SQLPerformance.com
SQLkiwi blog
@SQL_Kiwi