Need output in single row

Question

Need output in single row

New persopn

SSCarpal Tunnel

Points: 4019
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October 29, 2015 at 12:41 pm

#306128

Hi All,
I need out put in single row for below 2 queries using joins
SELECT [total_physical_memory_kb] / 1024 AS [Total_Physical_Memory_In_MB],
CPU_Count AS NumberofCPU
FROM [master].[sys].[dm_os_sys_memory]
CROSS JOIN sys.dm_os_sys_info
SELECT d.NAME,(SUM(mf.size) * 8 / 1024) / 1024 AS Size_GBs
FROM sys.master_files mf INNER JOIN sys.databases d
ON d.database_id = mf.database_id GROUP BY d.NAME
Order by (SUM(mf.size) * 8 / 1024) DESC

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Eirikur Eiriksson SSC Guru Points: 182882 More actions · Answer 1

New persopn (10/29/2015)
Hi All,
I need out put in single row for below 2 queries using joins
SELECT [total_physical_memory_kb] / 1024 AS [Total_Physical_Memory_In_MB],
CPU_Count AS NumberofCPU
FROM [master].[sys].[dm_os_sys_memory]
CROSS JOIN sys.dm_os_sys_info
SELECT d.NAME,(SUM(mf.size) * 8 / 1024) / 1024 AS Size_GBs
FROM sys.master_files mf INNER JOIN sys.databases d
ON d.database_id = mf.database_id GROUP BY d.NAME
Order by (SUM(mf.size) * 8 / 1024) DESC

Quick suggestion

😎

SELECT

[total_physical_memory_kb] / POWER(2,10) AS [Total_Physical_Memory_In_MB]

,CPU_Count AS NumberofCPU

,X.DBSTRING

FROM [master].[sys].[dm_os_sys_memory]

CROSS JOIN sys.dm_os_sys_info

CROSS APPLY

(

SELECT

STUFF((SELECT

N', ' + d.NAME + N' (' +

CONVERT(NVARCHAR(20),(SUM(mf.size) * 8) / POWER(2,20),0)

+ N' Gb)'

FROM sys.master_files mf INNER JOIN sys.databases d

ON d.database_id = mf.database_id GROUP BY d.NAME

Order by SUM(mf.size) DESC

FOR XML PATH(''),TYPE).value('.[1]','NVARCHAR(MAX)'),1,2,'')

) AS X(DBSTRING)

RPSQL Hall of Fame Points: 3229 More actions · Answer 2

;WITH QUERY1 ( Total_Physical_Memory_In_MB,NumberofCPU )

AS (SELECT [total_physical_memory_kb] / 1024 AS [Total_Physical_Memory_In_MB],

CPU_Count AS NumberofCPU

FROM [master].[sys].[dm_os_sys_memory]

CROSS JOIN sys.dm_os_sys_info

),

QUERY2 ( DBNAME,Size_GBs )

AS ( SELECT d.NAME as DBNAME,(SUM(mf.size) * 8 / 1024) / 1024 AS Size_GBs

FROM sys.master_files mf INNER JOIN sys.databases d

ON d.database_id = mf.database_id GROUP BY d.NAME

)

SELECT DBNAME,Size_GBs,Total_Physical_Memory_In_MB,NumberofCPU

FROM Query1 , Query2

Luis Cazares SSC Guru Points: 183698 More actions · Answer 3

RPSql (10/29/2015)
;WITH QUERY1 ( Total_Physical_Memory_In_MB,NumberofCPU )
AS (SELECT [total_physical_memory_kb] / 1024 AS [Total_Physical_Memory_In_MB],
CPU_Count AS NumberofCPU
FROM [master].[sys].[dm_os_sys_memory]
CROSS JOIN sys.dm_os_sys_info
),
QUERY2 ( DBNAME,Size_GBs )
AS ( SELECT d.NAME as DBNAME,(SUM(mf.size) * 8 / 1024) / 1024 AS Size_GBs
FROM sys.master_files mf INNER JOIN sys.databases d
ON d.database_id = mf.database_id GROUP BY d.NAME
)
SELECT DBNAME,Size_GBs,Total_Physical_Memory_In_MB,NumberofCPU
FROM Query1 , Query2

No need to use CTEs when you're working with single row views.

SELECT d.NAME,

(SUM(mf.size) * 8 / 1024) / 1024 AS Size_GBs,

[total_physical_memory_kb] / 1024 AS [Total_Physical_Memory_In_MB],

CPU_Count AS NumberofCPU

FROM [master].[sys].[dm_os_sys_memory]

CROSS JOIN sys.dm_os_sys_info

CROSS JOIN sys.master_files mf

INNER JOIN sys.databases d ON d.database_id = mf.database_id

GROUP BY d.NAME,

[total_physical_memory_kb],

CPU_Count

ORDER BY (SUM(mf.size) * 8 / 1024) DESC;

By the way, you have the semicolon in the wrong side of the query. 😉

Luis C.
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Are you seriously taking the advice and code from someone from the internet without testing it? Do you at least understand it? Or can it easily kill your server?

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New persopn SSCarpal Tunnel Points: 4019 More actions · Answer 4

Thanks for your help..

Once final thing i want to add below query to above please suggest

SELECT servicename, service_account

FROM sys.dm_server_services