Hi,
I've have this kind of string,
dr strange~('2', '8', '6', '1', '13', '18')~('dcc23eb8-ea79-46ea-81e8-022c0752a31e', 'cfe164e3-4e1d-4292-9016-1aa5aef5bf07', '77481c15-1eda-4c0b-8c5c-168479b3c7cf', 'f39f33c7-09de-4bb4-9f07-ea93d04fdb47', '719707f8-8931-4e25-ac15-28c55284af1a', '733fe23b-d053-4d54-bb96-fe03573cf79d', '4ffb80d8-3c1a-4dcc-a3d6-f44865105123', 'c0b35951-5ecf-4fe2-85d4-580051caf1f5', '1dc4a64a-6859-4f98-be87-8e6507b4dc42', '4150771f-8dee-45b2-8661-c9890e94d2f1', '1850dd6e-2e03-49da-b0b4-e16ed24f371d')~('6', '2', '4', '5', '3', '1')~('3', '4', '2', '1', '6', '5')~0~900000000~30~100~2021-01-01 00:00:00~2022-05-03 00:00:00
The separator is ~ . It is tilde
How to split and access the array[0] ?
Please help
Arrays do not exist in SQL Server, But strings can still be split and referenced by their ordinal ('ItemNumber' in the following).
This code relies on the existence of the legendary DelimitedSplit8K function – code and thorough explanation can be found here.
DECLARE @x VARCHAR(8000);
SET @x
= 'dr strange~(''2'', ''8'', ''6'', ''1'', ''13'', ''18'')~(''dcc23eb8-ea79-46ea-81e8-022c0752a31e'', ''cfe164e3-4e1d-4292-9016-1aa5aef5bf07'', ''77481c15-1eda-4c0b-8c5c-168479b3c7cf'', ''f39f33c7-09de-4bb4-9f07-ea93d04fdb47'', ''719707f8-8931-4e25-ac15-28c55284af1a'', ''733fe23b-d053-4d54-bb96-fe03573cf79d'', ''4ffb80d8-3c1a-4dcc-a3d6-f44865105123'', ''c0b35951-5ecf-4fe2-85d4-580051caf1f5'', ''1dc4a64a-6859-4f98-be87-8e6507b4dc42'', ''4150771f-8dee-45b2-8661-c9890e94d2f1'', ''1850dd6e-2e03-49da-b0b4-e16ed24f371d'')~(''6'', ''2'', ''4'', ''5'', ''3'', ''1'')~(''3'', ''4'', ''2'', ''1'', ''6'', ''5'')~0~900000000~30~100~2021-01-01 00:00:00~2022-05-03 00:00:00';
SELECT split.ItemNumber
,split.Item
FROM dbo.DelimitedSplit8K(@x, '~') split;
Results are as follows:
If you haven't even tried to resolve your issue, please don't expect the hard-working volunteers here to waste their time providing links to answers which you could easily have found yourself.
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