IIF-function gives errors

• r_slot

  Ten Centuries

  Points: 1379

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  January 29, 2013 at 4:41 am

  #288555

  Folks,

  I am using SQL Server 2012 Express Edition and want to make use of the new IIF-function. I am using the following code:

  IIF(Rank=1,'Gold',IIF(Rank =2,'Silver', 'Bronze'))

  Rank is a databasefield.

  My problem is that (when working in the criteria pane of Studio) I am getting the following error:

  An expression of non-boolean type specified in a context where a condition is expected, near '('

  It looks like IIF is not recognized??

  Working in de sql pane of Studio the error is something like:

  Error in list of function arguments: '=' not recognized.

  Unable to parse query text..

  I have tried almost everything to get the problem solved, but nothing seems to work.

  Can anyone get me out of this mess?

  Grz,

  Robert

• Ant-Green

  SSC Guru

  Points: 113544

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  January 29, 2013 at 4:50 am

  #1582028

  no longer applicable

• Adi Cohn-120898

  SSC-Dedicated

  Points: 33944

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  January 29, 2013 at 6:04 am

  #1582072

  IIF is a function that is used to return a value. Just like other functions (for example getdate()), it can't be written on its own without setting it's value to a variable or without select statement that is using it. See my code example:

  create table MyTable (Rank int);

  insert into MyTable values (1),(2),(3);

  select IIF(Rank=1,'Gold',IIF(Rank =2,'Silver', 'Bronze'))

  from MyTable;

  Adi

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• r_slot

  Ten Centuries

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  January 29, 2013 at 6:14 am

  #1582077

  Adi,

  Thanks: everything is working well now. I apologize for the mixing up the threads.

  Grz,

  Robert