How to Find "include columns"

  • How can i find "include columns" in any index ?

    sys.sysindexes doesn't provide its metadata information

    -------Bhuvnesh----------
    I work only to learn Sql Server...though my company pays me for getting their stuff done;-)

  • sys.index_columns has a 0/1 column named is_included_column;

    here's a script example that pulls some of that info out into a comma delimited list that i use for scripting out indexes:

    SELECT

    SCH.schema_id, SCH.[name] AS schema_name,

    OBJS.[object_id], OBJS.[name] AS object_name,

    IDX.index_id, ISNULL(IDX.[name], '---') AS index_name,

    partitions.Rows, partitions.SizeMB, IndexProperty(OBJS.[object_id], IDX.[name], 'IndexDepth') AS IndexDepth,

    IDX.type, IDX.type_desc, IDX.fill_factor,

    IDX.is_unique, IDX.is_primary_key, IDX.is_unique_constraint,

    ISNULL(Index_Columns.index_columns_key, '---') AS index_columns_key,

    ISNULL(Index_Columns.index_columns_include, '---') AS index_columns_include

    FROM tempdb.sys.objects OBJS

    INNER JOIN tempdb.sys.schemas SCH ON OBJS.schema_id=SCH.schema_id

    INNER JOIN tempdb.sys.indexes IDX ON OBJS.[object_id]=IDX.[object_id]

    INNER JOIN (

    SELECT

    [object_id], index_id, SUM(row_count) AS Rows,

    CONVERT(numeric(19,3), CONVERT(numeric(19,3), SUM(in_row_reserved_page_count+lob_reserved_page_count+row_overflow_reserved_page_count))/CONVERT(numeric(19,3), 128)) AS SizeMB

    FROM tempdb.sys.dm_db_partition_stats STATS

    GROUP BY [object_id], index_id

    ) AS partitions

    ON IDX.[object_id]=partitions.[object_id]

    AND IDX.index_id=partitions.index_id

    CROSS APPLY (

    SELECT

    LEFT(index_columns_key, LEN(index_columns_key)-1) AS index_columns_key,

    LEFT(index_columns_include, LEN(index_columns_include)-1) AS index_columns_include

    FROM

    (

    SELECT

    (

    SELECT COLS.[name] + ',' + ' '

    FROM tempdb.sys.index_columns IXCOLS

    INNER JOIN tempdb.sys.columns COLS

    ON IXCOLS.column_id = COLS.column_id

    AND IXCOLS.[object_id] = COLS.[object_id]

    WHERE IXCOLS.is_included_column = 0

    AND IDX.[object_id] = IXCOLS.[object_id]

    AND IDX.index_id = IXCOLS.index_id

    ORDER BY key_ordinal

    FOR XML PATH('')

    ) AS index_columns_key,

    (

    SELECT COLS.[name] + ',' + ' '

    FROM tempdb.sys.index_columns IXCOLS

    INNER JOIN tempdb.sys.columns COLS

    ON IXCOLS.column_id = COLS.column_id

    AND IXCOLS.[object_id] = COLS.[object_id]

    WHERE IXCOLS.is_included_column = 1

    AND IDX.[object_id] = IXCOLS.[object_id]

    AND IDX.index_id = IXCOLS.index_id

    ORDER BY index_column_id

    FOR XML PATH('')

    ) AS index_columns_include

    ) AS Index_Columns

    ) AS Index_Columns

    ORDER BY

    SCH.[name],

    OBJS.[name],

    IDX.[name]

    :

    Lowell


    --help us help you! If you post a question, make sure you include a CREATE TABLE... statement and INSERT INTO... statement into that table to give the volunteers here representative data. with your description of the problem, we can provide a tested, verifiable solution to your question! asking the question the right way gets you a tested answer the fastest way possible!

  • @lowell

    i am not able to see the required "include column" . i can only see the system related info.

    -------Bhuvnesh----------
    I work only to learn Sql Server...though my company pays me for getting their stuff done;-)

  • Bhuvnesh (8/26/2010)


    sys.sysindexes doesn't provide its metadata information

    No it won't. sysindexes is deprecated and only included for backward compatibility with SQL 2000. Since SQL 2000 did not have include columns, that view won't show them.

    Gail Shaw
    Microsoft Certified Master: SQL Server, MVP, M.Sc (Comp Sci)
    SQL In The Wild: Discussions on DB performance with occasional diversions into recoverability

    We walk in the dark places no others will enter
    We stand on the bridge and no one may pass
  • Bhuvnesh (8/26/2010)


    @lowell

    i am not able to see the required "include column" . i can only see the system related info.

    run my script against any database; look at the column index_columns_include (last in the list)

    you can then rip apart the code for more details.

    Lowell


    --help us help you! If you post a question, make sure you include a CREATE TABLE... statement and INSERT INTO... statement into that table to give the volunteers here representative data. with your description of the problem, we can provide a tested, verifiable solution to your question! asking the question the right way gets you a tested answer the fastest way possible!

  • doh the script i posted was coded for tempdb specifically, this will work in any old database:

    SELECT

    SCH.schema_id, SCH.[name] AS schema_name,

    OBJS.[object_id], OBJS.[name] AS object_name,

    IDX.index_id, ISNULL(IDX.[name], '---') AS index_name,

    partitions.Rows, partitions.SizeMB, IndexProperty(OBJS.[object_id], IDX.[name], 'IndexDepth') AS IndexDepth,

    IDX.type, IDX.type_desc, IDX.fill_factor,

    IDX.is_unique, IDX.is_primary_key, IDX.is_unique_constraint,

    ISNULL(Index_Columns.index_columns_key, '---') AS index_columns_key,

    ISNULL(Index_Columns.index_columns_include, '---') AS index_columns_include

    FROM sys.objects OBJS

    INNER JOIN sys.schemas SCH ON OBJS.schema_id=SCH.schema_id

    INNER JOIN sys.indexes IDX ON OBJS.[object_id]=IDX.[object_id]

    INNER JOIN (

    SELECT

    [object_id], index_id, SUM(row_count) AS Rows,

    CONVERT(numeric(19,3), CONVERT(numeric(19,3), SUM(in_row_reserved_page_count+lob_reserved_page_count+row_overflow_reserved_page_count))/CONVERT(numeric(19,3), 128)) AS SizeMB

    FROM sys.dm_db_partition_stats STATS

    GROUP BY [object_id], index_id

    ) AS partitions

    ON IDX.[object_id]=partitions.[object_id]

    AND IDX.index_id=partitions.index_id

    CROSS APPLY (

    SELECT

    LEFT(index_columns_key, LEN(index_columns_key)-1) AS index_columns_key,

    LEFT(index_columns_include, LEN(index_columns_include)-1) AS index_columns_include

    FROM

    (

    SELECT

    (

    SELECT COLS.[name] + ',' + ' '

    FROM sys.index_columns IXCOLS

    INNER JOIN sys.columns COLS

    ON IXCOLS.column_id = COLS.column_id

    AND IXCOLS.[object_id] = COLS.[object_id]

    WHERE IXCOLS.is_included_column = 0

    AND IDX.[object_id] = IXCOLS.[object_id]

    AND IDX.index_id = IXCOLS.index_id

    ORDER BY key_ordinal

    FOR XML PATH('')

    ) AS index_columns_key,

    (

    SELECT COLS.[name] + ',' + ' '

    FROM sys.index_columns IXCOLS

    INNER JOIN sys.columns COLS

    ON IXCOLS.column_id = COLS.column_id

    AND IXCOLS.[object_id] = COLS.[object_id]

    WHERE IXCOLS.is_included_column = 1

    AND IDX.[object_id] = IXCOLS.[object_id]

    AND IDX.index_id = IXCOLS.index_id

    ORDER BY index_column_id

    FOR XML PATH('')

    ) AS index_columns_include

    ) AS Index_Columns

    ) AS Index_Columns

    ORDER BY

    SCH.[name],

    OBJS.[name],

    IDX.[name]

    Lowell


    --help us help you! If you post a question, make sure you include a CREATE TABLE... statement and INSERT INTO... statement into that table to give the volunteers here representative data. with your description of the problem, we can provide a tested, verifiable solution to your question! asking the question the right way gets you a tested answer the fastest way possible!

  • Lowell (8/26/2010)


    doh the script i posted was coded for tempdb specifically, this will work in any old database:

    SELECT

    SCH.schema_id, SCH.[name] AS schema_name,

    OBJS.[object_id], OBJS.[name] AS object_name,

    IDX.index_id, ISNULL(IDX.[name], '---') AS index_name,

    partitions.Rows, partitions.SizeMB, IndexProperty(OBJS.[object_id], IDX.[name], 'IndexDepth') AS IndexDepth,

    IDX.type, IDX.type_desc, IDX.fill_factor,

    IDX.is_unique, IDX.is_primary_key, IDX.is_unique_constraint,

    ISNULL(Index_Columns.index_columns_key, '---') AS index_columns_key,

    ISNULL(Index_Columns.index_columns_include, '---') AS index_columns_include

    FROM sys.objects OBJS

    INNER JOIN sys.schemas SCH ON OBJS.schema_id=SCH.schema_id

    INNER JOIN sys.indexes IDX ON OBJS.[object_id]=IDX.[object_id]

    INNER JOIN (

    SELECT

    [object_id], index_id, SUM(row_count) AS Rows,

    CONVERT(numeric(19,3), CONVERT(numeric(19,3), SUM(in_row_reserved_page_count+lob_reserved_page_count+row_overflow_reserved_page_count))/CONVERT(numeric(19,3), 128)) AS SizeMB

    FROM sys.dm_db_partition_stats STATS

    GROUP BY [object_id], index_id

    ) AS partitions

    ON IDX.[object_id]=partitions.[object_id]

    AND IDX.index_id=partitions.index_id

    CROSS APPLY (

    SELECT

    LEFT(index_columns_key, LEN(index_columns_key)-1) AS index_columns_key,

    LEFT(index_columns_include, LEN(index_columns_include)-1) AS index_columns_include

    FROM

    (

    SELECT

    (

    SELECT COLS.[name] + ',' + ' '

    FROM sys.index_columns IXCOLS

    INNER JOIN sys.columns COLS

    ON IXCOLS.column_id = COLS.column_id

    AND IXCOLS.[object_id] = COLS.[object_id]

    WHERE IXCOLS.is_included_column = 0

    AND IDX.[object_id] = IXCOLS.[object_id]

    AND IDX.index_id = IXCOLS.index_id

    ORDER BY key_ordinal

    FOR XML PATH('')

    ) AS index_columns_key,

    (

    SELECT COLS.[name] + ',' + ' '

    FROM sys.index_columns IXCOLS

    INNER JOIN sys.columns COLS

    ON IXCOLS.column_id = COLS.column_id

    AND IXCOLS.[object_id] = COLS.[object_id]

    WHERE IXCOLS.is_included_column = 1

    AND IDX.[object_id] = IXCOLS.[object_id]

    AND IDX.index_id = IXCOLS.index_id

    ORDER BY index_column_id

    FOR XML PATH('')

    ) AS index_columns_include

    ) AS Index_Columns

    ) AS Index_Columns

    ORDER BY

    SCH.[name],

    OBJS.[name],

    IDX.[name]

    YES it works 🙂 thanks

    -------Bhuvnesh----------
    I work only to learn Sql Server...though my company pays me for getting their stuff done;-)

Viewing 7 posts - 1 through 7 (of 7 total)

You must be logged in to reply to this topic. Login to reply