June 11, 2008 at 8:35 am
Comments posted to this topic are about the item how to find duplicated rows in a table
June 18, 2008 at 12:29 am
edit: this should be one of the most basic queries ever. so, i have been surprised why you have choosen to add an identity column and querying the table twice with joins, etc.
shouldn't the script below suit your needs?
from t1 (NOLOCK)
group by y, x
having count(1) > 1
June 18, 2008 at 1:41 am
Infact, I didin't understand why you wrote like that code.
Where is the difference from below code.
I think It's very easy.
SELECT * FROM t1 WHERE y IN (
SELECT y FROM t1
GROUP BY y
June 18, 2008 at 2:07 am
this has gotta be the most pathetic script i've ever seen...
I'm surprised SSC even published this!!
Right there with Babe
June 18, 2008 at 2:51 am
you can use the following
COUNT(y) AS How_Many_Times
GROUP BY x, y
HAVING (COUNT(y) > 1)[/font]
I don't understand 1.why do you have to add a rowid!! 2.what is the purpose of adding a third column (z) with a default value of zero!!!
June 18, 2008 at 6:09 am
ABHILASH DHONGDI (6/18/2008)this has gotta be the most pathetic script i've ever seen... I'm surprised SSC even published this!!
ABHILASH DHONGDI (6/18/2008)
My thoughts, exactly. You can pick any line in the article and find problems with it. Awful.
June 18, 2008 at 8:41 am
I would have to agree with the other posts...
this script stinks on ice.
How does this warrant a hyperlink to the "solution script".
Lets keep the quality of the site high....
Fortunately, it usually is
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