Help on how to count guests in hotel every day

  • murgatroid (1/30/2013)


    This is very nearly the same type of problem discussed in Phil Factor's SQL Speed Phreak challenge http://ask.sqlservercentral.com/questions/1227/the-subscription-list-sql-problem.html, which is also discussed nicely here http://www.simple-talk.com/sql/performance/writing-efficient-sql-set-based-speed-phreakery/. Besides being a good read, I think that you could use the winning code easily enough, substituting days for months and guests for subscribers.

    Heavens to murgatroid!

    I'd seen that article and forgotten about it. Thanks for reminding me.


    My mantra: No loops! No CURSORs! No RBAR! Hoo-uh![/I]

    My thought question: Have you ever been told that your query runs too fast?

    My advice:
    INDEXing a poor-performing query is like putting sugar on cat food. Yeah, it probably tastes better but are you sure you want to eat it?
    The path of least resistance can be a slippery slope. Take care that fixing your fixes of fixes doesn't snowball and end up costing you more than fixing the root cause would have in the first place.

    Need to UNPIVOT? Why not CROSS APPLY VALUES instead?[/url]
    Since random numbers are too important to be left to chance, let's generate some![/url]
    Learn to understand recursive CTEs by example.[/url]
    [url url=http://www.sqlservercentral.com/articles/St

  • I get the same results both ways, even for days with no guests of one gender or no guests at all.

    CREATE TABLE #Guests (checkin date, checkout date, FullName varchar(50), Gender char(1))

    INSERT INTO #Guests

    SELECT '10/12/2012', '10/16/2012', 'Corky Doe','M' UNION ALL

    SELECT '12/12/2012', '12/17/2012', 'Janice Doe','F' UNION ALL

    SELECT '11/12/2012', '11/24/2012', 'Howard Stern','M' UNION ALL

    SELECT '12/12/2012', '12/13/2012', 'Abagail Johnson','F' UNION ALL

    SELECT '12/12/2012', '12/15/2012', 'Teddy Sanft','M' UNION ALL

    SELECT '12/12/2012', '12/18/2012', 'John Overton','M' UNION ALL

    SELECT '12/12/2012', '12/19/2012', 'Sally Jenson','F' UNION ALL

    SELECT '10/20/2012', '12/12/2012', 'Tiffany Blue','F'

    DECLARE @StartOfMonth DATE = '2012-12-01';

    WITH Calendar AS (

    SELECT TOP (DAY(DATEADD(mm,DATEDIFF(mm,-1,@StartOfMonth),-1)))

    [Day]=DATEADD(day, number - 1, @StartOfMonth)

    FROM [master].dbo.spt_values Tally

    WHERE [Type] = 'P' AND Number BETWEEN 1 AND 31)

    SELECT [Day]

    , Guests=ISNULL(COUNT(FullName), 0)

    , MaleGuests=ISNULL(SUM(CASE Gender WHEN 'M' THEN 1 END), 0)

    , FemaleGuests=ISNULL(SUM(CASE Gender WHEN 'F' THEN 1 END), 0)

    , Guests2=COUNT(FullName)

    , MaleGuests2=SUM(CASE Gender WHEN 'M' THEN 1 else 0 END)

    , FemaleGuests2=SUM(CASE Gender WHEN 'F' THEN 1 else 0 END)

    FROM Calendar

    LEFT JOIN #Guests ON [Day] >= checkin AND [Day] < checkout

    GROUP BY [Day]

    DROP TABLE #Guests


    Puto me cogitare, ergo puto me esse.
    I think that I think, therefore I think that I am.

  • srienstr (1/31/2013)


    I get the same results both ways, even for days with no guests of one gender or no guests at all.

    CREATE TABLE #Guests (checkin date, checkout date, FullName varchar(50), Gender char(1))

    INSERT INTO #Guests

    SELECT '10/12/2012', '10/16/2012', 'Corky Doe','M' UNION ALL

    SELECT '12/12/2012', '12/17/2012', 'Janice Doe','F' UNION ALL

    SELECT '11/12/2012', '11/24/2012', 'Howard Stern','M' UNION ALL

    SELECT '12/12/2012', '12/13/2012', 'Abagail Johnson','F' UNION ALL

    SELECT '12/12/2012', '12/15/2012', 'Teddy Sanft','M' UNION ALL

    SELECT '12/12/2012', '12/18/2012', 'John Overton','M' UNION ALL

    SELECT '12/12/2012', '12/19/2012', 'Sally Jenson','F' UNION ALL

    SELECT '10/20/2012', '12/12/2012', 'Tiffany Blue','F'

    DECLARE @StartOfMonth DATE = '2012-12-01';

    WITH Calendar AS (

    SELECT TOP (DAY(DATEADD(mm,DATEDIFF(mm,-1,@StartOfMonth),-1)))

    [Day]=DATEADD(day, number - 1, @StartOfMonth)

    FROM [master].dbo.spt_values Tally

    WHERE [Type] = 'P' AND Number BETWEEN 1 AND 31)

    SELECT [Day]

    , Guests=ISNULL(COUNT(FullName), 0)

    , MaleGuests=ISNULL(SUM(CASE Gender WHEN 'M' THEN 1 END), 0)

    , FemaleGuests=ISNULL(SUM(CASE Gender WHEN 'F' THEN 1 END), 0)

    , Guests2=COUNT(FullName)

    , MaleGuests2=SUM(CASE Gender WHEN 'M' THEN 1 else 0 END)

    , FemaleGuests2=SUM(CASE Gender WHEN 'F' THEN 1 else 0 END)

    FROM Calendar

    LEFT JOIN #Guests ON [Day] >= checkin AND [Day] < checkout

    GROUP BY [Day]

    DROP TABLE #Guests

    Sorry. I think I gave you a bad answer without thinking to much about it.

    I believe the ISNULL was just a carryover from my original solution where it was needed.


    My mantra: No loops! No CURSORs! No RBAR! Hoo-uh![/I]

    My thought question: Have you ever been told that your query runs too fast?

    My advice:
    INDEXing a poor-performing query is like putting sugar on cat food. Yeah, it probably tastes better but are you sure you want to eat it?
    The path of least resistance can be a slippery slope. Take care that fixing your fixes of fixes doesn't snowball and end up costing you more than fixing the root cause would have in the first place.

    Need to UNPIVOT? Why not CROSS APPLY VALUES instead?[/url]
    Since random numbers are too important to be left to chance, let's generate some![/url]
    Learn to understand recursive CTEs by example.[/url]
    [url url=http://www.sqlservercentral.com/articles/St

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