extracting column values when a part of the column value is known

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extracting column values when a part of the column value is known

t.mounika01

Mr or Mrs. 500

Points: 585
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August 21, 2014 at 8:52 pm

#289363

hi
How can we extract a column values from database if we know a part of that column value.
For ex: if I have values for a column called statements like this:
(I am good Gal)
(you are a good boy) and so on..
and I want to extract all the statements that have a part called 'good'
what is the best way to query this?

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Eirikur Eiriksson SSC Guru Points: 182947 More actions · Answer 1

Quick thought, use the LIKE operator

USE tempdb;

GO

DECLARE @TEST TABLE

(

TEST_ID INT IDENTITY(1,1) NOT NULL PRIMARY KEY CLUSTERED

,TEST_STRING VARCHAR(50) NOT NULL

);

INSERT INTO @TEST(TEST_STRING)

VALUES

('I am a bad Gal')

,('I am a good Gal')

,('This is an old horse')

,('This is a good horse')

,('I am a good boy')

,('I am a naugthy boy');

SELECT

*

FROM @TEST T

WHERE T.TEST_STRING LIKE '%good%';

Results

TEST_ID TEST_STRING

----------- ---------------------

2 I am a good Gal

4 This is a good horse

5 I am a good boy

t.mounika01 Mr or Mrs. 500 Points: 585 More actions · Answer 2

What to do if we want to replace the word 'good' with 'bad' in all those sentences?

I wrote it like this:

REPLACE(columnname,'good','bad')

Is there any other way to do this?

Ed Wagner SSC Guru Points: 287026 More actions · Answer 3

Using the REPLACE function is the simplest way to do it. Assuming there aren't any unusual requirements, that's exactly the way I'd do it.

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t.mounika01 Mr or Mrs. 500 Points: 585 More actions · Answer 4

t.mounika01

Mr or Mrs. 500

Points: 585

August 22, 2014 at 12:46 pm

#1740379

Thank you all for the help

Luis Cazares SSC Guru Points: 183706 More actions · Answer 5

Note that you might replace strings you don't want them to be replaced.

INSERT INTO @TEST(TEST_STRING)

VALUES

('I am a bad Gal')

,('I am a good Gal')

,('Oh my goodness! There''s no more goodwill')

,('He''s a patient with Osgood–Schlatter disease');

SELECT

*, REPLACE(TEST_STRING, 'good', 'bad')

FROM @TEST T

WHERE T.TEST_STRING LIKE '%good%';

Luis C.
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Eirikur Eiriksson SSC Guru Points: 182947 More actions · Answer 6

Luis Cazares (8/22/2014)
Note that you might replace strings you don't want them to be replaced.
INSERT INTO @TEST(TEST_STRING)
VALUES
('I am a bad Gal')
,('I am a good Gal')
,('Oh my goodness! There''s no more goodwill')
,('He''s a patient with Osgood–Schlatter disease');
SELECT
*, REPLACE(TEST_STRING, 'good', 'bad')
FROM @TEST T
WHERE T.TEST_STRING LIKE '%good%';

DECLARE @STR VARCHAR(50) = 'That an absolute @£$%'

SELECT REPLACE(REPLACE(REPLACE(REPLACE(@STR,'e @','ly'),'£',' a '),'$','brilliant'),'%',' point!')

extracting column values when a part of the column value is known

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