February 11, 2013 at 8:40 am
dwain.c (2/11/2013)
No idea because I don't know what Day 01, Day 02, etc. are supposed to represent.
;WITH Punches AS (
SELECT *
,rn=(ROW_NUMBER() OVER (PARTITION BY EmployeeID ORDER BY punchTime)-1)/2
FROM @table)
SELECT EmployeeID
,[Full_name] = MAX([Full_name])
,ClockIN=MIN(punchTime)
,ClockOUT=MAX(punchTime)
,date_start=CONVERT(VARCHAR(10),MIN(punchtime),111)
,date_end=CONVERT(VARCHAR(10),MIN(punchtime),111)
,day_name=DATEPART(dw,MIN(punchTime))
,Hrs=DATEDIFF(minute,MIN(punchTime), MAX(punchTime))/60.
,[day_value]= (SELECT day_value FROM TAT_Shiftpatterns WHERE day_name = 'Day 0' + CAST(DATEPART(dw,MIN(punchTime)) AS varchar) and Employee_number = '778' )
,[work_pattern] = MAX([work_pattern])
,[Hrs_diff] =DATEDIFF(minute,MIN(punchTime), MAX(punchTime))/60. - (SELECT day_value FROM TAT_Shiftpatterns WHERE day_name = 'Day 0' + CAST(DATEPART(dw,MIN(punchTime)) AS varchar) and Employee_number = '778' )
FROM Punches a
INNER JOIN [TAT_Shiftpatterns] b ON b.Employee_number = a.EmployeeID
GROUP BY EmployeeID, rn
by running the above code i am getting the expected output, but i have to hard code the employee number. Is there any alternative to this approach.
Thanks in advance
February 11, 2013 at 6:02 pm
p.ramchander (2/11/2013)
dwain.c (2/11/2013)
No idea because I don't know what Day 01, Day 02, etc. are supposed to represent.
;WITH Punches AS (
SELECT *
,rn=(ROW_NUMBER() OVER (PARTITION BY EmployeeID ORDER BY punchTime)-1)/2
FROM @table)
SELECT EmployeeID
,[Full_name] = MAX([Full_name])
,ClockIN=MIN(punchTime)
,ClockOUT=MAX(punchTime)
,date_start=CONVERT(VARCHAR(10),MIN(punchtime),111)
,date_end=CONVERT(VARCHAR(10),MIN(punchtime),111)
,day_name=DATEPART(dw,MIN(punchTime))
,Hrs=DATEDIFF(minute,MIN(punchTime), MAX(punchTime))/60.
,[day_value]= (SELECT day_value FROM TAT_Shiftpatterns WHERE day_name = 'Day 0' + CAST(DATEPART(dw,MIN(punchTime)) AS varchar) and Employee_number = '778' )
,[work_pattern] = MAX([work_pattern])
,[Hrs_diff] =DATEDIFF(minute,MIN(punchTime), MAX(punchTime))/60. - (SELECT day_value FROM TAT_Shiftpatterns WHERE day_name = 'Day 0' + CAST(DATEPART(dw,MIN(punchTime)) AS varchar) and Employee_number = '778' )
FROM Punches a
INNER JOIN [TAT_Shiftpatterns] b ON b.Employee_number = a.EmployeeID
GROUP BY EmployeeID, rn
by running the above code i am getting the expected output, but i have to hard code the employee number. Is there any alternative to this approach.
Thanks in advance
I think you need to read up a bit on GROUP BY. This is what I would do:
;WITH Punches AS (
SELECT *
,rn=(ROW_NUMBER() OVER (PARTITION BY EmployeeID ORDER BY punchTime)-1)/2
FROM @table)
SELECT EmployeeID
,[Full_name] = MAX([Full_name])
,ClockIN=MIN(punchTime)
,ClockOUT=MAX(punchTime)
,date_start=CONVERT(VARCHAR(10),MIN(punchtime),111)
,date_end=CONVERT(VARCHAR(10),MIN(punchtime),111)
,day_name=DATEPART(dw,MIN(punchTime))
,Hrs=DATEDIFF(minute,MIN(punchTime), MAX(punchTime))/60.
,[day_value]='Day 0' + CAST(DATEPART(dw,MIN(punchTime)) AS varchar)
,[work_pattern] = MAX([work_pattern])
,[Hrs_diff] =DATEDIFF(minute,MIN(punchTime), MAX(punchTime))/60. - (SELECT day_value FROM TAT_Shiftpatterns WHERE day_name = 'Day 0' + CAST(DATEPART(dw,MIN(punchTime)) AS varchar) and Employee_number = '778' )
FROM Punches a
INNER JOIN [TAT_Shiftpatterns] b ON b.Employee_number = a.EmployeeID
GROUP BY EmployeeID, rn
Not tested but it should work.
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The path of least resistance can be a slippery slope. Take care that fixing your fixes of fixes doesn't snowball and end up costing you more than fixing the root cause would have in the first place.
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Learn to understand recursive CTEs by example.[/url]
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