CharIndex Manipulation (SQL 2012). Select Case Statement to remove Part of String after one or two specific characters

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CharIndex Manipulation (SQL 2012). Select Case Statement to remove Part of String after one or two specific characters

Pack_Star

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June 3, 2015 at 4:50 am

#317894

Hi All,
I have an Address column that I need to Substring. I want to remove part of the string after either, or both of the following characters i.e ',' OR '*'
Example Record 1. Elland **REQUIRES BOOKING IN***
Example Record 2. Theale, Nr Reading, Berkshire
Example Record 3. Stockport
How do I achieve this in a CASE Statement?
The following two case statements return the correct results, but I some how need to combine them into a single Statement?
,LEFT(Address ,CASE WHEN CHARINDEX(',',Address) =0
THEN LEN(Address )
ELSE CHARINDEX(',' ,Address ) -1 END) AS 'Town Test'
,LEFT(Address ,CASE WHEN CHARINDEX('*',Address ) =0
THEN LEN(Address)
ELSE CHARINDEX('*' ,Address ) -1 END) AS 'Town Test2'
Thanks in advance

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spaghettidba SSC Guru Points: 105732 More actions · Answer 1

Duplicate post. Replies here please: http://www.sqlservercentral.com/Forums/FindPost1691082.aspx

-- Gianluca Sartori

Phil Parkin SSC Guru Points: 247180 More actions · Answer 2

Pack_Star (6/3/2015)
Hi All,
I have an Address column that I need to Substring. I want to remove part of the string after either, or both of the following characters i.e ',' OR '*'
Example Record 1. Elland **REQUIRES BOOKING IN***
Example Record 2. Theale, Nr Reading, Berkshire
Example Record 3. Stockport
How do I achieve this in a CASE Statement?
The following two case statements return the correct results, but I some how need to combine them into a single Statement?
,LEFT(Address ,CASE WHEN CHARINDEX(',',Town) =0
THEN LEN(Address )
ELSE CHARINDEX(',' ,Address ) -1 END) AS 'Town Test'
,LEFT(Address ,CASE WHEN CHARINDEX('*',Address ) =0
THEN LEN(Address)
ELSE CHARINDEX('*' ,Address ) -1 END) AS 'Town Test2'
Thanks in advance

What is the difference between 'Town' and 'Address' and which is the sample data referring to?

Pack_Star Mr or Mrs. 500 Points: 547 More actions · Answer 3

Hi,

Sorry typo on my part. Address/Town are the same column.

The examples are sample records found in the Address Column.

Thanks

Phil Parkin SSC Guru Points: 247180 More actions · Answer 4

OK. Here is a hack for you.

with addresses

as (select address = 'Elland **REQUIRES BOOKING IN***'

union all

select 'Theale, Nr Reading, Berkshire'

union all

select 'Stockport'

)

select *

,left(address, case when charindex(',', address) = 0 then len(address)

else charindex(',', address) - 1

end) as 'Town Test'

,left(address, case when charindex('*', address) = 0 then len(address)

else charindex('*', address) - 1

end) as 'Town Test2'

,left(address, case when charindex(',', replace(address,'*',',')) = 0 then len(address)

else charindex(',', replace(address,'*',',')) - 1

end) as 'Town Test3'

from addresses;

Phil Parkin SSC Guru Points: 247180 More actions · Answer 5

spaghettidba (6/3/2015)
Duplicate post. Replies here please: http://www.sqlservercentral.com/Forums/FindPost1691082.aspx

So sorry. I missed this.

Pack_Star Mr or Mrs. 500 Points: 547 More actions · Answer 6

Hi Phil,

Absolutely perfect!!!

I have been struggling with this for a couple of days.

Many Thanks

Phil Parkin SSC Guru Points: 247180 More actions · Answer 7

Pack_Star (6/3/2015)
Hi Phil,
Absolutely perfect!!!
I have been struggling with this for a couple of days.
Many Thanks
Nigel

That's too long! Post here straight after day 1 in future 🙂

ScottPletcher SSC Guru Points: 101200 More actions · Answer 8

If you just need whichever comes first, I suggest:

with addresses

as (select address = 'Elland **REQUIRES BOOKING IN***'

union all

select 'Theale, Nr Reading, Berkshire'

union all

select 'Stockport'

)

select address

,left(address, PATINDEX('%[,*]%', address + ',') - 1) as address_trimmed

from addresses;

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