Database Weekly - June 2, 2008
A look back at the news from the week including Windows 7 and taking an unwired vacation.
2008-06-01
31 reads
A look back at the news from the week including Windows 7 and taking an unwired vacation.
2008-06-01
31 reads
Seeking to recognize DBAs for the work they do, the Exceptional DBA Awards are open for nominations. Steve Jones talks a bit about the event.
2008-05-29
35 reads
As the number of different software/technologies increases exponentially, does specializing limit an IT professional's ability to move around?
2008-05-28
40 reads
Steve Jones talks about alternative hybrids, in this bi-monthly update on automotive news.
2008-05-27
493 reads
2008-05-23
36 reads
A new feature for SQL Server? Steve Jones talks about a very interesting job posting from Microsoft.
2008-05-21
32 reads
2008-05-20
44 reads
Do the people that build SQL Server really work with it? Steve Jones shares a short story from a recent trip to the Pacific Northwest.
2008-05-19
41 reads
How can you find good employees? Steve Jones offers a few tips on what has worked for him in the past.
2008-05-18
33 reads
Steve Jones looks at the performance of column changes, petaflop computing, and a few ways to beef up your DBA skills.
2008-05-17
38 reads
By Steve Jones
It’s time for T-SQL Tuesday again and this is a great prompt to start...
How I used AI for this postChatGPT to generate images based on info specifically...
By ReviewMyDB
My T-SQL Tuesday #202 entry for Marlon Ribunal's invitation on memorable SQL Server outages....
Hello everyone, Last week we performed an upgrade of our SQL Server instance, moving...
Comments posted to this topic are about the item Adding new column with DEFAULT
I've got a web application for my side business. I've added a SQL Server...
Which number will the COUNT() return after executing the following statements:
DROP TABLE IF EXISTS #test; CREATE TABLE #test (id INT) INSERT INTO #test (id) SELECT * FROM GENERATE_SERIES(1, 3) AS gs ; ALTER TABLE #test ADD flag BIT CONSTRAINT DF_#test_flag DEFAULT 0; go UPDATE #test SET flag = 0 WHERE id = 1 UPDATE #test SET flag = 1 WHERE id = 2 INSERT INTO #test (id) VALUES (4) SELECT COUNT(*) FROM #test AS t WHERE flag = 0See possible answers