24 Hours of PASS
I’m fairly certain Jack Bauer isn’t involved with this new initiative from PASS. Just as I’m also certain I won’t...
2009-08-03
751 reads
I’m fairly certain Jack Bauer isn’t involved with this new initiative from PASS. Just as I’m also certain I won’t...
2009-08-03
751 reads
I like to blog about technical topics and community, not personal stuff. However, this is a community post. A number...
2009-08-01
628 reads
PASS is trying to find better ways to reach out to SQL Bloggers. They’re going to experiment with taking advantage...
2009-07-31
1,331 reads
I thought I had an interesting answer to the question. Unfortunately Adam Machanic, who has been working in this specific...
2009-07-31
1,332 reads
UPDATE: This post is incorrect. Adam nailed it in the comments. I explain my mistake here.
A question came up over...
2009-07-28
1,883 reads
Steve Jones, through a series of comments, emails, blackmail, back-alley deals & tons of whining, agreed to let me review a...
2009-07-24
600 reads
Do you know how to start a conversation or how to join one? I usually wait for a pause and...
2009-07-21
673 reads
Do you want to get a glimpse into how the Microsoft Field Engineers would go about troubleshooting performance issues on...
2009-07-20
793 reads
By SQLPals
How to Clear the SSMS Cache (SSMS 21 and Later) Updated...
By Arun Sirpal
“What exactly did it do on my server?” is the first question a DBA...
By James Serra
Microsoft shared a broad set of Fabric, Power BI, and SQL updates at FabCon...
Comments posted to this topic are about the item Let's Talk Certifications
Comments posted to this topic are about the item The Hidden Security Risks of...
Comments posted to this topic are about the item The Empty Aggregate
I have this table in a SQL Server 2025 database:
CREATE TABLE [dbo].[CustomerOrder] ( [OrderID] [int] NULL, [CustomerID] [int] NULL, [total] [money] NULL ) ON [PRIMARY] GOWhat is returned from this code? (answers are for the sum and then the count)
SELECT SUM(total) AS sum,
COUNT(total) AS count
FROM dbo.CustomerOrder;
See possible answers