T-SQL Tuesday #17 – APPLY Knowledge
It’s that time of the month again… again. Time for T-SQL Tuesday! This month’s event is being hosted by Matt...
2011-04-12
1,237 reads
It’s that time of the month again… again. Time for T-SQL Tuesday! This month’s event is being hosted by Matt...
2011-04-12
1,237 reads
Every career, whether on purpose or accident, is a journey from one job or project to another. To achieve great...
2011-04-11
570 reads
I’m going to SQL Rally! Are you going to SQL Rally? Have you heard of SQL Rally?
What’s SQL Rally?
I’m glad...
2011-04-07
420 reads
Use extended events; they work – and make you appear magical.
– “Write a SQL blog post in 11 words or less”...
2011-04-04
618 reads
Yesterday, I went in for my re-take of the MCM written exam. If you recall, I failed the exam last...
2011-03-29
560 reads
We’ve seen a few summaries come through by now, so I’m going to throw mine into the mix. To recap...
2011-03-29
673 reads
Previously, in a TSQL2sDay index summary post, I started a series on the DMV sys.dm_db_index_operational_stats. The series investigates how the...
2011-03-26
841 reads
Last week I spoke at the TechFuse event in Minnesota – out at Mystic Lake Casino. As I mentioned in the...
2011-03-24
471 reads
A couple weeks ago, I got some pretty great new. The book proposal that I had submitted to Apress was...
2011-03-22
624 reads
Twin Cities Code Camp will be hitting the University of Minnesota Campus again next month. This is a biannual event...
2011-03-18
574 reads
By Chris Yates
The New Arena of Leadership The role of the Chief Data Officer is no...
Presenting you with an updated version of our sp_snapshot procedure, allowing you to easily...
SELECT * feels convenient, but in SQL Server it bloats I/O, burns network bandwidth,...
I've noticed several instances of what looks like a recursive insert with the format:...
Comments posted to this topic are about the item Cleaning Up the Cloud
Comments posted to this topic are about the item The Maximum Value in the...
I have a table with this data:
TravelLogID CityID StartDate EndDate 1 1 2025-01-01 2025-01-06 2 2 2025-01-01 2025-01-06 3 3 2025-01-01 2025-01-06 4 4 2025-01-01 2025-01-06 5 5 2025-01-01 2025-01-06I run this code:
SELECT IDENT_CURRENT('TravelLog')I get the value 5 back. Now I do this:
SET IDENTITY_INSERT dbo.TravelLog ON INSERT dbo.TravelLog ( TravelLogID, CityID, StartDate, EndDate ) VALUES (25, 5, '2025-09-12', '2025-09-17') SET IDENTITY_INSERT dbo.TravelLog OFFI now run this code.
DBCC CHECKIDENT(TravelLog) GO INSERT dbo.TravelLog ( CityID, StartDate, EndDate ) VALUES (4, '2025-10-14', '2025-10-17') GOWhat is the value for TravelLogID for the row I inserted for CityID 4 and dates starting on 14 Oct 2025? See possible answers