Re-blog – November 25 – December 1
Welcome to the Friday Re-Blog summary post. The aim of these posts is to bring some old posts that newer...
2011-12-02
495 reads
Welcome to the Friday Re-Blog summary post. The aim of these posts is to bring some old posts that newer...
2011-12-02
495 reads
Welcome to the second of a few sponsor interview posts from SQL Saturday 99. After reading Arnie Rowland’s (Blog | @ArnieRowland)...
2011-12-01
768 reads
I’m probably going to have to put together a new SQL video, because I’ve been accepted to speak at SQL...
2011-12-01
550 reads
2011-11-30
1,477 reads
SQL Server 2012 is coming to 12 cities next year. Is your city on the list? It can be – or...
2011-11-29
858 reads
Welcome to the first of a few sponsor interview posts from SQL Saturday 99. After reading Arnie Rowland’s (Blog | @ArnieRowland)...
2011-11-29
509 reads
Do you have $5 you could re-direct from a cup of coffee to a donation on men’s health issues?
If you...
2011-11-28
480 reads
You can find the slides and scripts from Monday’s Extended Events session for the Adelaide SQL Server User Group in the...
2011-11-25
520 reads
Welcome to the Friday Re-Blog summary post. The aim of these posts is to bring some old posts that newer...
2011-11-25
888 reads
In the past week, I’ve had a number of requests for a list of the WordPress plug-ins that I use. ...
2011-11-21
1,137 reads
By gbargsley
We’ve all been there. Someone walks up and asks, “Is SQL Server having issues?”...
By Chris Yates
In the beginning, there was OLTP – Online Transaction Processing. Fast, reliable, and ruthlessly...
One thing I’ve always loved about the Scooby-Doo cartoon is that he never solved...
Hello SQL Server 2022 16.0.4212.1 running on a Windows Server 2025 Std,V 24H2, SO...
i have subscription of github copilot which i can access in vs 2022 comunity...
Comments posted to this topic are about the item Password Guidance
What happens if you run the following code in SQL Server 2022+?
declare @t1 table (id int); insert into @t1 (id) values (NULL), (1), (2), (3); select count(*) from @t1 where @t1.id is distinct from NULL;See possible answers