MDX Puzzle #6
As we continue with the puzzles, I will continue to introduce new MDX functions. In this puzzle the requirements are...
2010-08-25
631 reads
As we continue with the puzzles, I will continue to introduce new MDX functions. In this puzzle the requirements are...
2010-08-25
631 reads
After spending a week in Tampa, FL at a client site I've had some time to unwind and reflect back...
2010-08-23
959 reads
So, I was recently asked if you could display a vertical bar on a line graph to denote the last...
2010-08-11
3,334 reads
Again I want to apologize for the slow posting of the solution to this puzzle, but I have been hard...
2010-08-10
583 reads
In this three part series SQL Server MVP Andy Leonard will discuss SSIS Design Patterns.
Speaker: Andy Leonard
Add To Outlook:...
2010-08-08
1,072 reads
We are just about a week away from probably the biggest FREE training event to ever take place in Baton...
2010-08-06
554 reads
Do you have a challenging SQL Server or .Net issue that is causing you to have sleepless nights? Well, we...
2010-08-03
516 reads
Writing YTD totals and Running totals using T-SQL can take a little effort. However, with MDX it's not too difficult. ...
2010-08-01
551 reads
This puzzle may not have been much of a challenge, but it introduced two new MDX concepts. I have to...
2010-07-30
1,561 reads
Now that we are into the third quarter of 2010 I decided to post an update of my 2nd quarter...
2010-07-28
1,012 reads
By Zikato
A cryptic message, a book cipher hidden in art provenance records, and a trail...
By Steve Jones
A customer was trying to compare two tables and capture a state as a...
By Zikato
When I'm looking at a query, I bet it's bad if I see... a...
Telp Cso: (0821)8200174 Jl. Cokro Aminoto No.28, Kisaran Kota, Kec. Kota Kisaran Barat, Kabupaten...
Telp Cso: (0821)8200174 Jl. Merdeka No.39, Proklamasi, Kec. Siantar Bar., Kota Pematang Siantar, Sumatera...
Telp Cso: (0821)8200174 Jl. Asia, Simpang, Jl. Bakaran Batu No.1 C, Sei Rengas II,...
In SQL Server 2025, I have a table (dbo.UserPermission) that contains this data:
UserID UserPermissions 15 23 37 4 NULLWhat is returned when I run this code:
select bit_count(UserPermissions) as PermissionCount from dbo.UserPermission where UserID = 4;See possible answers